Answer:
2408.1 °C
Explanation:
Given data:
Mass of oxygen = 1.70 g
Volume occupy = 9.75 L
Pressure of gas = 799 torr (799/760 = 1.1 atm)
Temperature = ?
Solution:
Formula:
PV = nRT
First of all we will determine the number of moles of oxygen.
Number of moles = mass/ molar mass
Number of moles = 1.70 g/ 32 g/mol
Number of moles = 0.05 mol
Now we will put the values.
R = general gas constant = 0.0821 atm.L/ mol.K
T = PV/nR
T = 1.1 atm× 9.75 L /0.05 mol ×0.0821 atm.L/ mol.K
T = 10.725 /0.004
T = 2681.25 K
kelvin to °C
2681.25 K - 273.15 = 2408.1 °C
