Volume of solution in liters:
5.00 x 10² mL / 1000 => 0.5 L
number of moles:
mass of solute / molar mass
21.1 / 119.0 => 0.1773 moles
Molarity = number of moles / volume
M = 0.1773 / 0.5
M = 0.355 mol/L
Answer C
<span>hope this helps!</span>
There seems to be a mistake. If u mistyped the 'h', then the reaction is single replacement.
Answer: (a) There are 0.428 moles present in 12 g of 
molecule.
(b) There are 2 moles present in 
particles of oxygen.
Explanation:
(a). The mass of nitrogen molecule is given as 12 g.
As the molar mass of is 28 g/mol so its number of moles are calculated as follows.
So, there are 0.428 moles present in 12 g of molecule.
(b). According to the mole concept, 1 mole of every substance contains 
atoms.
Therefore, moles present in particles are calculated as follows.
So, there are 2 moles present in particles of oxygen.
Answer: Please see answer below
Explanation:
The steps of glycogen degradation is as follows from this order.
--->Hormonal signals trigger glycogen breakdown.
1. Glycogen is (de)branched by hydrolysis of α‑1,6‑glycosidic linkages.
2. Blocks consisting of three glucosyl residues are moved by remodeling of α‑1,4‑glycosidic linkages.
3.[Glucose 1‑phosphate is cleaved from the non reducing ends of glycogen and converted to glucose 6‑phosphate.
--->Glucose 6‑phosphate undergoes further metabolic processing
The degradation of Glycogen follows three steps:
(1) the release of glucose 1-phosphate from glycogen,
(2) the remodeling of the glycogen substrate to permit further degradation, and
(3) the conversion of glucose 1-phosphate into glucose 6-phosphate for further metabolism.
(https://www.ncbi.nlm.nih.gov/books/NBK21190)
