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Anon25 [30]
2 years ago
6

a fictitious element X is composed of 15.0% of the isotope X-51, 15.0% of the isotope X-52, and 70.0% of the isotope X-53. Estim

ate the atomic mass of element C
Chemistry
1 answer:
MatroZZZ [7]2 years ago
6 0
(0.15)(51) + (0.15)(52) + (0.7)(53)
=53 amu
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Which of the following is true about the kinetic molecular theory?
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Answer: (B) Pressure is due to the collisions of the gas particles with the walls of the container.

Option B helps to explain the factor behind gas collision under high pressure.

Explanation: Kinetic molecular theory explains the behaviour and movement of gas particles when they are in motion. It states that gas particles are always in continuous motion and are perfectly elastic in nature.

Kinetic molecular theory can be explained using both Boyle's law and Charles's law.

•Few Assumptions of Kinetic Molecular Theory.

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Question 8<br>Which one of the following salts does not contain water of crystallisation?​
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Baking soda is sodium bicarbonate in anhydrous form without any water of crystallisation and it is widely used as dry fire extinguisher because of its alkali nature.
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Why can the same earthquake have different ratings on the 2 scales.
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The scales are different
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2 years ago
When 943 J of heat is added to 10 grams of oil at 28˚C , the temperature increases to 89˚C. What is the specific heat of the oil
IgorLugansk [536]

Answer: 1.55 Jg°C

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 943 joules

Mass of oil = 10g

C = ? (let unknown value be Z)

Φ = (Final temperature - Initial temperature)

= 89°C - 28°C = 61°C

Then, Q = MCΦ

943 J = 10g x Z x 61°C

943J = 610g°C x Z

Z = (943J / 610g°C)

Z = 1.55 Jg°C

Thus, the specific heat of the oil is 1.55 Jg°C

7 0
3 years ago
3. Methane (CH4) behaves as an ideal gas under standard temperature and pressure conditions. What volume is occupied by 1 kg of
AlekseyPX

Answer:

1711.11L

Explanation:

Given parameters:

Mass of methane = 1kg = 1000

Temperature of gas = 35°C

Pressure of the gas = 0.9atm

Converting to the temperature to kelvin, we have:

               35+ 273 = 308k

Solution

From the given parameters, we can solve this problem using the ideal gas equation which is combination of the gas laws. It is expressed below:

                                         PV = nRT              .......................(i)

Where P is the pressure of the gas

             V is the volume of the gas

             n is the number of moles

             R is the gas constant

             T is the temperature

Now, from the above parameters, we have two unknowns which are n and V.

To find the number of moles n, we use the expression below:

         number of moles = \frac{mass}{molar mass}

        molar mass of methane = 12 + (4x1) = 16g/mol

       Number of moels of methane =  \frac{1000}{16} = 62.5mole

Now that we know the number of moles, we can make the unknown Volume the subject of the formula:

                     V = \frac{nRT}{P}

                     V =  \frac{62.5 x 0.082 x 308}{0.9} = 1711.11L

7 0
3 years ago
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