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Anon25 [30]
3 years ago
6

a fictitious element X is composed of 15.0% of the isotope X-51, 15.0% of the isotope X-52, and 70.0% of the isotope X-53. Estim

ate the atomic mass of element C
Chemistry
1 answer:
MatroZZZ [7]3 years ago
6 0
(0.15)(51) + (0.15)(52) + (0.7)(53)
=53 amu
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Spell out the full name of the compounds<br> Help plz
Agata [3.3K]

Answer:

propanal

Explanation:

hope this helps :)

8 0
3 years ago
What is the molarity of a 5.00x10^2 mL solution containing 21.1 g of potassium bromide (KBr)? The molar mass of KBr is 119.0 g/m
Dominik [7]
Volume of solution in liters:

5.00 x 10² mL / 1000 => 0.5 L 

number of moles:

mass of solute / molar mass

21.1 / 119.0 => 0.1773 moles

Molarity = number of moles / volume 

M = 0.1773 / 0.5

M = 0.355 mol/L

Answer C

<span>hope this helps!</span>
5 0
3 years ago
Read 2 more answers
Fe + Ph(NO3)2 ==&gt; Pb + Fe(NO3)2
Ahat [919]
There seems to be a mistake. If u mistyped the 'h', then the reaction is single replacement.
5 0
3 years ago
How many moles are present in
olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

4 0
3 years ago
Arrange the steps of glycogen degradation in their proper order. Hormonal signals trigger glycogen breakdown. Glucose 6‑phosphat
Otrada [13]

Answer: Please see answer below

Explanation:

The steps of glycogen degradation is as follows from this order.

--->Hormonal signals trigger glycogen breakdown.

1. Glycogen is (de)branched by hydrolysis of α‑1,6‑glycosidic linkages.

2. Blocks consisting of three glucosyl residues are moved by remodeling of α‑1,4‑glycosidic linkages.

3.[Glucose 1‑phosphate is cleaved from the non reducing ends of glycogen and converted to glucose 6‑phosphate.

--->Glucose 6‑phosphate undergoes further metabolic processing

The  degradation  of Glycogen follows  three steps:

(1) the release of glucose 1-phosphate from glycogen,

(2) the remodeling of the glycogen substrate to permit further degradation, and

(3) the conversion of glucose 1-phosphate into glucose 6-phosphate for further metabolism.

(https://www.ncbi.nlm.nih.gov/books/NBK21190)

4 0
3 years ago
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