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faltersainse [42]
3 years ago
6

Parallelograms ABDC and EFHG are similar. If side AC equals 4 units, side AB equals 16 units, and side EG equals 32 units, what

Mathematics
1 answer:
alexdok [17]3 years ago
4 0
Remember that sides AC and EG will correspond. By finding the ratio of the lengths of these sides, we can find the length of EF.
The ratio of 4 to 16 simplifies to 1:4. This means that every side in ABDC is 1/4th of its corresponding side in EFHG. 16 times 4 is 64, so EF has a length of 64 units.
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Answer:

C and B

Step-by-step explanation:

The correct option is option B and C. The necessary condition to prove that the opposite angles of a parallelogram are congruent:

C. Angle Addition Postulate.

B. Opposite sides are congruent

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3 years ago
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Find x?<br> In 3x - In(x - 4) = ln(2x - 1) +ln3
earnstyle [38]

Answer:

x = \displaystyle \frac{5 + \sqrt{17}}{2}.

Step-by-step explanation:

Because 3\, x is found in the input to a logarithm function in the original equation, it must be true that 3\, x > 0. Therefore, x > 0.

Similarly, because (x - 4) and (2\, x - 1) are two other inputs to the logarithm function in the original equation, they should also be positive. Therefore, x > 4.

Let a and b represent two positive numbers (that is: a > 0 and b > 0.) The following are two properties of logarithm:

\displaystyle \ln (a) + \ln(b) = \ln\left(a \cdot b\right).

\displaystyle \ln (a) - \ln(b) = \ln\left(\frac{a}{b}\right).

Apply these two properties to rewrite the original equation.

Left-hand side of this equation:

\begin{aligned}&\ln(3\, x) - \ln(x - 4)= \ln\left(\frac{3\, x}{x -4}\right)\end{aligned}

Right-hand side of this equation:

\ln(2\, x- 1) + \ln(3) = \ln\left(3 \left(2\, x - 1\right)\right).

Equate these two expressions:

\begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned}.

The natural logarithm function \ln is one-to-one for all positive inputs. Therefore, for the equality \begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned} to hold, the two inputs to the logarithm function have to be equal and positive. That is:

\displaystyle \frac{3\ x}{x - 4} = 3\, (2\, x - 1).

Simplify and solve this equation for x:

x^2 - 5\, x + 2 = 0.

There are two real (but not rational) solutions to this quadratic equation: \displaystyle \frac{5 + \sqrt{17}}{2} and \displaystyle \frac{5 - \sqrt{17}}{2}.

However, the second solution, \displaystyle \frac{5 - \sqrt{17}}{2}, is not suitable. The reason is that if x = \displaystyle \frac{5 - \sqrt{17}}{2}, then (x - 4), one of the inputs to the logarithm function in the original equation, would be smaller than zero. That is not acceptable because the inputs to logarithm functions should be greater than zero.

The only solution that satisfies the requirements would be \displaystyle \frac{5 + \sqrt{17}}{2}.

Therefore, x = \displaystyle \frac{5 + \sqrt{17}}{2}.

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3 years ago
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Musya8 [376]

Answer:

5x<12

Step-by-step explanation:

Five times x is equally 5x fewer than is equally < # 5x<12

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HEEELР ПОЖАЛУЙСТА HELР
seropon [69]

So for question one (about the equilateral triangle), you know any triangle equals 180 degrees. So an equilateral triangle has all equal angles, so 180/3 would equal 60 degrees for each angle.

Now for the first triangle out of the three isosceles.

You should know that there are two equal sides and one side that is not equal in a isosceles triangle.

So if one side is 34 degrees, and the other two are equal, then you first subtract 34 degrees from 180 degrees, because again, all triangles have 180 degrees. So 180-34 would equal to 146 degrees left. Now you divide 146 by two, because the other two angles are equal to each other. So 146/2 = 73 degrees for each of the remaining angles.

For the second triangle out of the three isosceles.

First, let's just calculate half of the triangle first. You already know two angles, 30 and 90 degrees (hence the 90 degree symbol).

So 30 + 90 would equal 120 degrees in total out of 180 degrees (because 1 triangle = 180 degrees).

So if you subtract 180-120 or 120 + ? = 180 to know the remaining angle of the half of the triangle, you would get 60 degrees left. And that also goes with the other side of the top angle of the entire triangle, so your answer for the second one would be 60 degrees. :-)

For the third triangle out of the three isosceles.

You know one angle is 75 degrees.

If you turn your screen a little bit (like about 90 degrees) to the left, you would see that two sides (with the x degree in the middle) is equal. So then know you know the other side of the triangle would also be 75 degrees, because one side that is equal has 75 degrees.

Now you have two 75 degrees, you add 75 + 75, which gives you 150 degrees now.

So obviously again, 180 degrees is the total amount of degrees in a triangle, and you want to know the last degree that would make the triangle equal to 180 degrees out of 150 degrees, so 180-150 or 150 + ? = 180, which gives you 30 degrees for x for the third isosceles triangle.

try doing the fourth one by yourself lol

5 0
3 years ago
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