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faltersainse [42]
3 years ago
6

Parallelograms ABDC and EFHG are similar. If side AC equals 4 units, side AB equals 16 units, and side EG equals 32 units, what

Mathematics
1 answer:
alexdok [17]3 years ago
4 0
Remember that sides AC and EG will correspond. By finding the ratio of the lengths of these sides, we can find the length of EF.
The ratio of 4 to 16 simplifies to 1:4. This means that every side in ABDC is 1/4th of its corresponding side in EFHG. 16 times 4 is 64, so EF has a length of 64 units.
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I need help with number 46 Thankyou
Over [174]
A²+B²=C²
6²+8²=C²
C²=100
C=10
Therefore the length of AB is 10 units
8 0
3 years ago
A skirt originally cost $10. How much will it cost if you sell it in Amazon with 25% mark-up price
san4es73 [151]

Answer:

$20.40

Step-by-step explanation:

20% off means that the new price of the skirt will be 80% of the original price:

$30(100%  – 20%) = $30(80%)

Converting the percent to a decimal gives:

$30(0.8) = $24.00

There is an additional 15% off the sale price of $24.00, so the final price is 85% of the sale price:

$24(100%  – 15%) = $24(85%)

Again converting the percent to a decimal gives:

$24(0.85) = $20.40

5 0
3 years ago
Write 42 as a product of prime numbers<br> 42=?<br> Please help
lisabon 2012 [21]
Hope i help <span>42/2= 21 
21 / 3 = 7 
Answer=2 x 3 x 7</span>
7 0
3 years ago
Read 2 more answers
Jeff drinks 2/3 of a glass of juice. write a fraction that is equivalent to 2/3
frutty [35]
Some fractions that are equivalent to 2/3 are 4/6 and 6/9
to find equivalent fractions, you just have to reduce the fraction or multiply both the top and bottom numbers by the same number to increase the fraction.
2/3 is as reduced as it can be, though.
8 0
3 years ago
The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean o
prohojiy [21]

Answer:

The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%

Step-by-step explanation:

For a normal random variable with mean Mu = 3.2 and standard deviation sd = 0.8 there is a distribution of the sample mean (MX) for samples of size 4, given by:

Z = (MX - Mu) / sqrt (sd ^ 2 / n) = (MX - 3.2) / sqrt (0.64 / 4) = (MX - 3.2) / 0.4

For a sample mean of 3.0, Z = (3 - 3.2) / 0.4 = -0.5

For a sample mean of 3.0, Z = (4 - 3.2) / 0.4 = 2.0

P (3.2 <MX <4) = P (-0.5 < Z <2.0) = 0.6687.

The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%

6 0
3 years ago
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