As we know that collision is elastic so we will have
also we can use momentum conservation
now from above two equations we will have
also we have
so both balls will separate after collision and move in opposite direction as the final velocities are opposite in sign
So correct answer will be
<em>D. The balls separate and move in opposite directions.</em>
Answer:
formula used K=F/∆l
∆l is the elongation of the spring
- F=10N
- ∆l=20mm===> 0.02m
- K=10N divided 0.02m= 500N/m
Nitrogen fixing bacteria changes dead plants and animals into ammonia compounds.
<h2>What is nitrogen fixation?</h2>
Atmospheric nitrogen is converted into nitrogen oxides by the action of lightning, which helps its incorporation into the soil.
<h3>Characteristics of Nitrogen fixing bacteria</h3>
- Nitrogen is fixed by these bacteria and other prokaryotes through various metabolic processes, which convert it into different usable compounds, such as ammonia (NH3) and ammonium ion (NH4+).
- These microorganisms can be found in soil and water, or as plant symbionts.
Therefore, we can conclude that nitrogen fixing bacteria fix nitrogen from the air, that is, they originate soluble compounds by plants, such as ammonia.
Learn more about nitrogen fixation here: brainly.com/question/14726009
Answer:
a. d₁/d₂ = 1.09 b. 0.054 mW
Explanation:
a. What is the ratio of the diameter of the first student's eardrum to that of the second student?
We know since the power is the same for both students, intensity I ∝ I/A where A = surface area of ear drum. If we assume it to be circular, A = πd²/4 where r = radius. So, A ∝ d²
So, I ∝ I/d²
I₁/I₂ = d₂²/d₁² where I₁ = intensity at eardrum of first student, d₁ = diameter of first student's eardrum, I₂ = intensity at eardrum of second student, d₂ = diameter of second student's eardrum.
Given that I₂ = 1.18I₁
I₂/I₁ = 1.18
Since I₁/I₂ = d₂²/d₁²
√(I₁/I₂) = d₂/d₁
d₁/d₂ = √(I₂/I₁)
d₁/d₂ = √1.18
d₁/d₂ = 1.09
So, the ratio of the diameter of the first student's eardrum to that of the second student is 1.09
b. If the diameter of the second student's eardrum is 1.01 cm. how much acoustic power, in microwatts, is striking each of his (and the other student's) eardrums?
We know intensity, I = P/A where P = acoustic power and A = area = πd²/4
Now, P = IA
= I₂A₂
= I₂πd₂²/4
= 1.18I₁πd₂²/4
Given that I₁ = 0.58 W/m² and d₂ = 1.01 cm = 1.01 × 10⁻² m
So, P = 1.18I₁πd₂²/4
= 1.18 × 0.58 W/m² × π × (1.01 × 10⁻² m)²/4
= 0.691244π × 10⁻⁴ W/4 =
2.172 × 10⁻⁴ W/4
= 0.543 × 10⁻⁴ W
= 0.0543 × 10⁻³ W
= 0.0543 mW
≅ 0.054 mW
There are
two things that you should remember while dealing with the "Lever Mechanical Advantage" problems:
1) The Effort Arm;
2) The Resistance Arm.
Some books label the Effort Arm as in-lever arm and the Resistance Arm as out-lever arm. (Physics Jargon that you need to remember in order to solve problems)
The Effort Arm is that "part" of the lever where the force can be applied. The Resistance Arm is where some mass is placed. In the diagram, as you can see, the mass is placed on one arm of the lever. Therefore, it is the Resistance Arm.
Now the formula for the "Mechanical Advantage(MA)" is:
Where
is the length of the Effort Arm(the subscript "e" stands for Effort), and
stands for the length of the Resistance Arm(here "r" stands for Resistance).
Plug in the values:
= 15m.
= 7m.
Therefore,
/
= 15/7 =
2.143 = MAThe correct answer is
option C(2.14).
-i
