2 years ago

A force of 10 N causes a spring to extend by 20 mm. Find: a) the spring constant of the spring in N/m

Physics

1 answer:

Mars2501 [29]2 years ago

6 0

Answer:

formula used K=F/∆l

∆l is the elongation of the spring

F=10N
∆l=20mm===> 0.02m
K=10N divided 0.02m= 500N/m

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A force of 10 N causes a spring to extend by 20 mm. Find: a) the spring constant of the spring in N/m​

A force of 10 N causes a spring to extend by 20 mm. Find: a) the spring constant of the spring in N/m