A baseball player throws a baseball at 42 m/s. If the other player catching the baseball is 18 m from the player, how much time
1 answer:
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The new velocity after 4 s is 40 m/s
The height of the spaceship above the ground after 5 seconds is 1,127.5 m
The given parameters for the first question;
- initial velocity of the car, u = 76 m/s
- acceleration of the car, a = - 9 m/s²
- time of motion, t = 4 s
The new velocity after 4 s is calculated as;
v = u + at
v = 76 + (-9)(4)
v = 76 - 36
v = 40 m/s
(5)
The given parameters;
- height above the ground, h = 500 m
- velocity of spaceship, u = 150 m/s
- time of motion, t = 5
The height of the spaceship above the ground after 5 seconds is calculated as;
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