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earnstyle [38]
3 years ago
14

Consider a cylinder initially filled with 9.33 10-4 m3 of ideal gas at atmospheric pressure. An external force is applied to slo

wly compress the gas at constant temperature to 1/6 of its initial volume. Calculate the work that is done. Note that atmospheric pressure is 1.013 105 Pa.
Physics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

Work done will be 78.76 J

Explanation:

We have given initial volume of the gas V_1=9.33\times 10^{-4}m^3

Pressure is given by P=1.013\times 10^5Pa

Final volume V_2=\frac{V_1}{6}=\frac{9.33\times 10^{-4}}{6}=1.555\times 10^{-4}m^3

Change in volume \Delta V=V_2-V_1=1.555\times 10^{-4}-9.33\times 10^{-4}=-7.775\times 10^{-4}m^3

We know that work done is given by

W=-Pdv=-1.013\times 10^5\times 7.775\times 10^{-4}=78.760J

Work done will be 78.76 J

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