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mote1985 [20]
3 years ago
14

Can u someone help me ? Plz

Mathematics
1 answer:
NARA [144]3 years ago
6 0
What is the question?
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What is the oblique asymptote of the function f(x) x^2+x-2/x+1
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f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}


\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
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Consequently, t<span>he limit of f(x) as x approaches infinity is x.

In other words, f(x) approaches the line y=x, 
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so oblique asymptote is y=x.

I'm Japanese, if you find some mistakes in my English, please let me know.</span>

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