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2 years ago

What is the mean absolute deviation of the data set? {12, 17, 12, 8,6)

Mathematics

1 answer:

ser-zykov [4K]2 years ago

8 0

Answer:The mean absolute deviation of the set of data is

2.24

Step-by-step explanation:

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(b) 33 is 75% of what number?

miskamm [114]

Your answer should be 44 lol

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2 years ago

Read 2 more answers

Sharon wants to make a graph to show the relationship between the number of tickets sold and the price of tickets sold. She plot

Masteriza [31]

The statement that best describes the graph is “It will not be spread out across the entire coordinate plane because in Step 3 Sharon plotted the independent variable on the y-axis.”

To add, graphing is a powerful tool for representing and interpreting numerical data. In addition, graphs and knowledge of algebra can be used to find the relationship between variables plotted on a scatter chart.

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3 years ago

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago

I need help with #18,20,22 and 24. Please show your work and I'm really thankful for your help as soon as possible!

Artist 52 [7]

I'll start 18 and 22 for you, and you should then be able to do the rest on your own!

For 18, what we literally do is apply the distance formula for all the points and add them up. For B to C, we get the distance between them to be
sqrt((x1-x2)^2+(y1-y2)^2)=sqrt((0-4)^2+(3-(-1))^2)=sqrt((-4)^2+4^2)=sqrt(16+16)=sqrt(32). Repeat the process for C to E, E and F, and F to B then add the results up to get your answer!

For 22, since the area of a rectangle is length*width (we know given the right angles and that the opposite sides are equal in how long they are), we can multiply 2 perpendicular lines, for example, BC and CE to get sqrt(32)*sqrt(8)=16 as the area

4 0

3 years ago

926/71 Explain how u got the answer

Gala2k [10]

Answer:

Step-by-step explanation:

926/71 = 13 Remainder 3

5 0

2 years ago