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Inessa05 [86]
3 years ago
10

A light year is defined as the distance that light can travel in 1 year. What is the value of 1 light year in meter? Show your c

omplete work. [Note: light travels 3 x 10^8 m in 1s.]
Physics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

d=9.462×10^15 meters

Explanation:

<u>Relation between distance, temps and velocity:</u>

d=v*t

t=1year*(365days/1year)*/(24hours/1day)*(3600s/1h)=31536000s

So:

1 light year=d=3*10^8m/s*3.154*10^7s=9.462×10^15 meters

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Galina-37 [17]

Answer:

Explanation:

weight on moon = 1/6* weight on earth

69.3=1/6*weight on earth

weight on earth = 69.3*6

weight on earth = 415.8 N

8 0
3 years ago
A piece of wire 29 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
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Answer:

Explanation:

Total length of the wire is 29 m.

Let the length of one piece is d and of another piece is 29 - d.

Let d is used to make a square.

And 29 - d is used to make an equilateral triangle.

(a)

Area of square = d²

Area of equilateral triangle = √3(29 - d)²/4

Total area,

A = d^{2}+\frac{\sqrt3}{4}\left ( 29-d \right )^{2}

Differentiate both sides with respect to d.

\frac{dA}{dt}=2d- \frac{\sqrt3}{4}\times 2(29-d)

For maxima and minima, dA/dt = 0

d = 8.76 m

Differentiate again we get the

\frac{d^{2}A}{dt^{2}}= + ve

(a) So, the area is maximum when the side of square is 29 m

(b) so, the area is minimum when the side of square is 8.76 m

8 0
3 years ago
1. A Zambeef delivery track travels 18 km north, 10 km east, and 16 km south. What is its final displacement from the origin?
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Answer:

2km

Explanation:

Given data

We are told that the direction traveled are

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Hence the displacement is defined as the distance away from the initial position is

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The displacement = 18-16= 2km

Hence the displacement is 2km

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