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3 years ago

If light has a speed of 122,000 mps in a transparent medium, what is the index of refraction of the medium? A. n = 1.52

Physics

1 answer:

castortr0y [4]3 years ago

3 0

Answer:

$A.\hspace{3}n=1.52$

Explanation:

The refractive index of a medium is a measure to know how much the speed of light within the medium is reduced. It can be calculated with the next equation:

$n=\frac{c}{v}$ (1)

Where:

$c=Speed\hspace{3}of\hspace{3}light\hspace{3}in\hspace{3}vacuum\\n=Refractive\hspace{3}index\\$

$v=Velocity\hspace{3}of\hspace{3}light\hspace{3}in\hspace{3}the\hspace{3}medium$

The speed of light in the vacuum is approximately 300,000 km/s. In order to work with the same units let's do the proper conversion with the velocity of the medium:

$122,000\frac{mi}{s} *\frac{1.60934km}{1mi}=196339.48\frac{km}{s}$

Finally, replacing the data in (1):

$n=\frac{300,000}{196339.48} =1.527965746\approx1.52$

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A bullet with a mass 2.25g is fired up into the air with a velocity of 187.5 m/s. What is the maximum height of the bullet

Ksivusya [100]

Answer:

1793.7m

Explanation:

From the principle of conservation of energy; the kinetic energy substended by the object equals the potential energy sustain by the object when it gets to its maximum position.

Now the kinetic energy; is

K.E = 1/2 × m × v2

Where m is mass

v is velocity

Hence.

K.E = 1/2 × 2.25 × (187.5)^2

Now this should be same with the potential energy which is given as;

P.E = m× g× h

Where m is mass of object

g is acceleration of free fall due to gravity = 9.8m/S2

h is maximum height substain by the object.

Hence P.E = 2.25 × 9.8 × h

From the foregoing analysis of energy conversation it implies;

1/2 × 2.25 × (187.5)^2 =2.25 × 9.8 × h

=> 1/2 × (187.5)^2 = 9.8 × h

=>1/2 × (187.5)^2 / 9.8 = h

=> 1793.69m = h

h= 1793.69m

h =1793.7m to 1 decimal place

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3 years ago

A battery is connected to a light bulb that has 3 of resistance . If there is 0.5 A of current flowing what is the voltage on th

Alenkasestr [34]

Answer:

1.5 V

Explanation:

E = IR = 0.5(3) = 1.5 V

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3 years ago

List the following types of electromagnetic radiation in order of increasing wavelength:(i) the gamma rays produced by a radioac

Naddik [55]

Answer:

In order of increasing wavelength, the answer is:

(i) The gamma rays produced by a radioactive nuclide used in medical imaging

(iv) The yellow light from sodium-vapor streetlights

(v) The red light of a light emitting diode, such as in a calculator display

(ii) Radiation from an FM radio station at 93.1 MHz on the dial

(iii) A radio signal from an AM radio station at 680kHz on the dial

Explanation:

First, you have to know that the wavelength of a sinusoidal wave traveling at a constant speed is given by:

λ $= \frac{v}{f}$

Where λ is the wavelength, $v$ is the constant speed and $f$ is the wave's frequency. In the case of electromagnetic radiation in free space, the constant speed is the speed of light.

From explained above, you can conclude that there is a proportionality relationship between the wavelength and the frequency, they are inversely proportional. That means: the highest frequency will have the shortest wavelength and vice-versa.

So, you have the following types:

(i) The gamma rays produced by a radioactive nuclide used in medical imaging

Frequency : Typically greater than $10^{19}$ Hz

(ii) Radiation from an FM radio station at 93.1 MHz on the dial

Frequency: 93.1 MHz

(iii) A radio signal from an AM radio station at 680 kHz on the dial

Frequency: 680 kHz

(iv) The yellow light from sodium-vapor streetlights

Frequency: Visible spectrum of approx. 508 - 526 THz

(v) The red light of a light-emitting diode, such as in a calculator display

Frequency: Visible spectrum of approx. 400 - 484 THz

Then, you have to organize them from the highest frequency to the smallest one (decreasing frequency), and as the highest frequency will have the shortest wavelength, you are going to have it organized in an increasing wavelength mode.

Then in order of increasing wavelength, the answer will be:

(i) , (iv), (v), (ii), (iii)

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3 years ago

A Hall probe, consisting of a rectangular slab of current-carrying material, is calibrated by placing it in a known magnetic fie

Citrus2011 [14]

Answer:

(a) 0.345 T

(b) 0.389 T

Solution:

As per the question:

Hall emf, $V_{Hall} = 20\ mV = 0.02\ V$

Magnetic Field, B = 0.10 T

Hall emf, $V'_{Hall} = 69\ mV = 0.069\ V$

Now,

Drift velocity, $v_{d} = \frac{V_{Hall}}{B}$

$v_{d} = \frac{0.02}{0.10} = 0.2\ m/s$

Now, the expression for the electric field is given by:

$E_{Hall} = Bv_{d}sin\theta$ (1)

And

$E_{Hall} = V_{Hall}d$

Thus eqn (1) becomes

$V_{Hall}d = dBv_{d}sin\theta$

where

d = distance

$B = \frac{V_{Hall}}{v_{d}sin\theta}$ (2)

(a) When $\theta = 90^{\circ}$

$B = \frac{0.069}{0.2\times sin90} = 0.345\ T$

(b) When $\theta = 60^{\circ}$

$B = \frac{0.069}{0.2\times sin60} = 0.398\ T$

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3 years ago

An Na ion has a charge of +1 and an O ion has a charge of –2. How many Na ions does one O ion need to balance charges

Aleonysh [2.5K]

Because Na⁺ ion lacks an electron and O²⁻ has two extra electrons extra, to balance the charge, we need 2 Na⁺ ions.

All ions, atoms and molecules want to get to the minimum energy state, and that state is when the ion, atom, or molecule is neutral, that's why all of them want to balance their charges.

7 0

3 years ago

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