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3 years ago

A rope vibrates every 0.5 s. what is the frequency of the waves?

Physics

2 answers:

julsineya [31]3 years ago

6 0

The rope vibrates every 0.5 s: it means that its period is

$T=0.5 s$

The frequency of an oscillation is equal to the reciprocal of the period:

$f=\frac{1}{T}$

Therefore, if we substitute T=0.5 s in the formula, we get:

$f=\frac{1}{0.5 s}=2 Hz$

umka2103 [35]3 years ago

4 0

F = 1/t
F = 1/0.5
F = 2Hz

Answer is 2Hz

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3 years ago

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Answer:

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So, in order to find the values of luminosity or mass of different stars, we take the luminosity or mass of sun as reference. Therefore, write the equation for a star and Sun, and divide them to get:

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where,

L = Luminosity of Sun

M = mass of Sun

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It is given that:

Mass of Star = 2M

Therefore, eqn (1) implies that:

Luminosity of star/L = (2M/M)^3.5

Luminosity of Star = (2)^3.5 L

Luminosity of Star = 11.3 L

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It is given that:

Luminosity of star = 3160 L

Therefore, eqn (1) implies that:

3160L/L = (Mass of Star/M)^3.5

taking ln on both sides:

ln (3160) = 3.5 ln(Mass of Star/M)

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