To develop this problem it is necessary to apply the Rayleigh Criterion (Angular resolution)criterion. This conceptos describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution. By definition is defined as:

Where,
= Wavelength
d = Width of the slit
= Angular resolution
Through the arc length we can find the radius, which would be given according to the length and angle previously described.
The radius of the beam on the moon is

Relacing 


Replacing with our values we have that,


Therefore the diameter of the beam on the moon is



Hence, the diameter of the beam when it reaches the moon is 7361.82m
Answer: First you must convert pound in kilogram, and feet in meter
Explanation:
To calculate momentum we use .
p=m*V
mass-m
speed-V
distance and time are used to calculate velocity(speed)
You are given :
mass- in pounds
for distance - in feet
before you do any calculation first you have to convert pounds in kilograms
and feet in meters.
Answer:
They move farther apart
Explanation:
When objects heat up they expand for example heating up a balloon makes it expand
It seems that you have missed the given options for the given statement above whether it is true or false. But anyway, the correct answer would be TRUE. It is true that one <span>of the most effective ways to evaluate data is to try to replicate it. Hope that this answer will help you. </span>