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3 years ago

14

camp oak gets 32 boxes of orange juice and 56 boxes of apple juice each self in the cupboard can hold 8 boxes of juice what is

the least number of shelves needed for all the juice boxes

1 answer:

Flura [38]3 years ago

7 0

32 boxes of oj + 56 boxes of aj = 90 boxes of juice
If a self can only hold 8 boxes of juice, then you need to divide 90 by 8.
90/8 = 11.25
This means that they need at least 12 shelves for all the Juice boxes.

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3 years ago

In a department store a desk costs £120. In a sale the price in reduced by 10%. How much is the desk reduced by

goldfiish [28.3K]

Answer:

£12

Step-by-step explanation:

£120 ×10/100

= £12.

That is the answer. Good luck

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3 years ago

7. A fundraising group charges $0.25 per cookie and has a daily expense of $18. Which of the

marissa [1.9K]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

Place the three functions in order from the fastest decreasing average rate of change to the slowest decreasing average rate of

victus00 [196]

Answer:

g(x), f(x) and h(x)

Step-by-step explanation:

Given

Interval: (0,3)

See attachment for functions f(x), g(x) and h(x)

Required

Order from fastest to slowest decreasing average rate of change

The average rate of change is calculated as:

$Rate = \frac{f(b) - f(a)}{b - a}$

In this case:

$(a,b) = (0,3)$

i.e.

$a = 0\\b=3$

For f(x)

$f(x) = 16(\frac{1}{2})^x$

$Rate = \frac{f(b) - f(a)}{b - a}$

$Rate = \frac{f(3) - f(0)}{3 - 0}$

$Rate = \frac{f(3) - f(0)}{3}$

Calculate f(3) and f(0)

$f(x) = 16(\frac{1}{2})^x$

$f(3) = 16(\frac{1}{2})^3 = 16 * \frac{1}{8} = 2$

$f(0) = 16(\frac{1}{2})^0 = 16 * 1 = 16$

So:

$Rate = \frac{f(3) - f(0)}{3}$

$Rate = \frac{2 - 16}{3}$

$Rate = -\frac{14}{3}$

For g(x)

$Rate = \frac{g(b) - g(a)}{b - a}$

$Rate = \frac{g(3) - g(0)}{3 - 0}$

$Rate = \frac{g(3) - g(0)}{3}$

From the table of g(x)

$g(3) = 1$

$g(1) = 27$

So:

$Rate = \frac{1 - 27}{3}$

$Rate = -\frac{26}{3}$

For h(x)

$Rate = \frac{h(b) - h(a)}{b - a}$

$Rate = \frac{h(3) - h(0)}{3 - 0}$

$Rate = \frac{h(3) - h(0)}{3}$

From the graph of h(x)

$h(3) = -3$

$h(0) = 4$

So:

$Rate = \frac{-3 - 4}{3}$

$Rate = -\frac{7}{3}$

So, the calculated rates of change are:

$f(x) = -\frac{14}{3}$ $= -4.67$

$g(x) = -\frac{26}{3}$ $=-8.67$

$h(x) = -\frac{7}{3}$ $=-2.33$

By comparison:

From the fastest decreasing to slowest, the order is: <em>g(x), f(x) and h(x)</em>

4 0

3 years ago

For a class picnic two teachers went to the same store to purchase drinks one teacher purchased 18 juice boxes and 32 bottles of

makkiz [27]

Cost of each juice boxes is $ 0.68 and cost of each water bottle is $ 0.24

<em><u>Solution:</u></em>

Let "j" be the cost of each juice box

Let "w" be the cost of each bottles of water

<em><u>One teacher purchased 18 juice boxes and 32 bottles of water and spent $19.92</u></em>

Therefore, we frame a equation as:

18 x cost of each juice box + 32 x cost of each bottles of water = 19.92

$18 \times j + 32 \times w = 19.92$

18j + 32w = 19.92 ------ eqn 1

<em><u>The other teacher Purchased 14 Juice Boxes and 26 Boxes of water and spent $15.76</u></em>

Therefore, we frame a equation as:

14 x cost of each juice box + 26 x cost of each bottles of water = 15.76

$14 \times j + 26 \times w = 15.76$

14j + 26w = 15.76 ----------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 7</u></em>

126j + 224w = 139.44 -------- eqn 3

<em><u>Multiply eqn 2 by 9</u></em>

126j + 234w = 141.84 ---------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

126j + 234w = 141.84

126j + 224w = 139.44

( - ) --------------------

10w = 2.4

Divide both sides by 10

w = 0.24

<em><u>Substitute w = 0.24 in eqn 1</u></em>

18j + 32(0.24) = 19.92

18j + 7.68 = 19.92

18j = 12.24

Divide both sides by 18

j = 0.68

Thus cost of each juice boxes is $ 0.68 and cost of each water bottle is $ 0.24

3 0

3 years ago