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Mariulka [41]
3 years ago
14

camp oak gets 32 boxes of orange juice and 56 boxes of apple juice each self in the cupboard can hold 8 boxes of  juice what is

the least number of shelves needed for all the juice boxes
Mathematics
1 answer:
Flura [38]3 years ago
7 0
32 boxes of oj + 56 boxes of aj = 90 boxes of juice
If a self can only hold 8 boxes of juice, then you need to divide 90 by 8.
90/8 = 11.25
This means that they need at least 12 shelves for all the Juice boxes.
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Please help asap! Really appreciate it . <br>a. 240<br>b. 210<br>c. 90<br>d. 300
Mice21 [21]

Answer: D) 300 degrees (counterclockwise)

================================================

We want to have segment PQ rotate around the center so that it lines up with segment RF. Put another way: we want point P to rotate around the center to have it line up with point R, and we want Q to rotate so that it moves to point F.

Going clockwise, this is a rotation of 60 degrees as the diagram below shows (each blue arc is 30 degrees, so in total it's 30+30 = 60). In that diagram, I'm only focusing on moving point P. Point Q moves in a similar fashion. Since 60 is not an answer, this means 360-60 = 300 must be the answer.

6 0
3 years ago
The number of members in an organization increases by an average of 150 members annually. There were 4,650 members in 1971. Choo
8_murik_8 [283]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=
luda_lava [24]

Let f(x) = x^3 - 2x - 2. Then differentiating, we get

f'(x) = 3x^2 - 2

We approximate f(x) at x_1=2 with the tangent line,

f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18

The x-intercept for this approximation will be our next approximation for the root,

10x - 18 = 0 \implies x_2 = \dfrac95

Repeat this process. Approximate f(x) at x_2 = \frac95.

f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}

Then

\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}

Once more. Approximate f(x) at x_3.

f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}

Then

\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}

Compare this to the actual root of f(x), which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0
2 years ago
An 80% confidence interval is found to be (0.52, 0.58) what is the sample proportion?
Mazyrski [523]

Answer: 55

Step-by-step explanation:

ape

3 0
3 years ago
Monica paid sales tax of $1.60 when she bought a new bike helmet. If the sales tax rate was 8%, how much did the store charge fo
Lapatulllka [165]
To find the total from the percent part you have, you divide the part by the percentage.
1.50÷0.05=30
The total is $30
The total the store charged, including sales tax, is $31.50.
5 0
3 years ago
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