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3 years ago

What is the value of 24/25 divided by 4/5

Mathematics

2 answers:

Naddik [55]3 years ago

5 0

$\frac{24}{25}*\frac{5}{4}\\\\\\=\frac{6}{5}$

Dimas [21]3 years ago

3 0

Answer:

1.2

Hope it helps :)

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Three times a number plus three times a second number is fifteen. Four times the first plus twice the second number is fourteen.

Alexxx [7]

Answer:

x = 2 | y = 3. ( 2,3 )

Step-by-step explanation:

2(3x + 3y = 15)

6x + 6y = 30

3(4x + 2y = 14)

12x + 6y = 42

- 6x. -6y. -30

6x = 12

÷ 6. ÷6

x = 2

3x + 3y = 15

3(2) + 3y = 15

6 + 3y = 15

-6. -6

3y = 9

÷3. ÷3

y = 3

3 0

3 years ago

O.<br> What is the greatest common factor (GCF) of 4 and 64?

Fantom [35]

Answer:

yes .

.... I think 4 is the GCF of 4&64

8 0

3 years ago

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

3 years ago

A botanical garden contains several cube-shaped planters. One planter

monitta

Answer:

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3 years ago

If Ajit brought 5 oranges for Rs 30 and sold each oranges at Rs 8 ,what did his gain percentage?

Dafna11 [192]

Answer:

33.3...%

Step-by-step explanation:

8 0

3 years ago