The answer would be you can’t simplify the first one but the second would be 15 square root 5

Hope this helps

Have a great day/night

Feel free to ask any questions

5 0

2 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

3 years ago

Read 2 more answers

The sum of 4 consecutive intergers is 50, what is the first interger in this relationship

Vesnalui [34]

Answer:

x = 11

Step-by-step explanation:

Consecutive means in a row

Let x be the first integer

x+1 is the second

x+2 is the third

x+3 is the 4th

The sum is 50

x+ x+1 + x+2 + x+3 = 50

Combine like terms

4x+6 = 50

Subtract 6 from each side

4x+6-6 = 50-6

4x = 44

Divide each side by 4

4x/4 = 44/4

x = 11

7 0

3 years ago

What is the square root of 189

valina [46]

Answer:

$3 \sqrt{21}$

Step-by-step explanation:

$\sqrt{189} = 3 \sqrt{21}$

7 0

3 years ago