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2 years ago

This is the graph of f(x). What is the value of f(2)? A. 2 B. 16 C. 8 D. 4

Mathematics

1 answer:

musickatia [10]2 years ago

8 0

Answer:

D. 4

Step-by-step explanation:

x=2, y=4 on the graph

Therefore, f(2)=4

Hope this helps!

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In a class of 55 students, 15 students like Math but not English and 18 students liked English but not Math. If 5 students did n

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See the venn-diagram in the picture.

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2 years ago

Find the sum of these polynomials. (2x^2+x+3)+(3x^2+2x+1)

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That would be the solution to this

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2 years ago

Read 2 more answers

Exercise 2.4.2: Proving statements about rational numbers with direct proofs. About Prove each of the following statements using

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Answer:

See Explanation

Step-by-step explanation:

(a) Proof: Product of two rational numbers

Using direct proofs.

Let the two rational numbers be A and B.

Such that:

$A = \frac{1}{2}$

$B = \frac{2}{3}$

The product:

$A * B = \frac{1}{2} * \frac{2}{3}$

$A * B = \frac{1}{1} * \frac{1}{3}$

$A * B = 1 * \frac{1}{3}$

$A * B = \frac{1}{3}$

Proved, because 1/3 is rational

(b) Proof: Quotient of a rational number and a non-zero rational number

Using direct proofs.

Let the two rational numbers be A and B.

Such that:

$A = \frac{1}{2}$

$B = \frac{2}{3}$

The quotient:

$A / B = \frac{1}{2} / \frac{2}{3}$

Express as product

$A / B = \frac{1}{2} / \frac{3}{2}$

$A / B = \frac{1*3}{2*2}$

$A / B = \frac{3}{4}$

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(c) x + y is rational (missing from the question)

Using direct proofs.

Let x and y be

Such that:

$x = \frac{1}{2}$

$y = \frac{2}{3}$

The sum:

$x + y = \frac{1}{2} + \frac{2}{3}$

Take LCM

$x + y = \frac{3+4}{6}$

$x + y = \frac{7}{6}$

Proved, because 7/6 is rational

<em>The above proof works for all values of A, B, x and y; as long as they are rational values</em>

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3 years ago

A nutrition laboratory wants to construct a 95% confidence interval for the mean sodium content of "reduced sodium" hot dogs. A

tatuchka [14]

Answer:

n > 96

Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg

Step-by-step explanation:

Given;

Standard deviation r= 25mg

Width of confidence interval w= 10mg

Confidence interval of 95%

Margin of error E = w/2 = 10mg/2 = 5mg

Z at 95% = 1.96

Margin of error E = Z(r/√n)

n = (Z×r/E)^2

n = (1.96 × 25/5)^2

n = (9.8)^2

n = 96.04

n > 96

Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg

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3 years ago

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Serjik [45]

Answer:

− 6 x + 3

Step-by-step explanation:

hope that helps :)

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2 years ago