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ziro4ka [17]
3 years ago
6

Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of

such a sample of the acid if the density of the solution is 1.504 g/ml?
Chemistry
1 answer:
dsp733 years ago
6 0
The first thing we need to do here is to recognize the unit of molarity and the units of the given percentage of nitric acid.

Molarity is mol HNO3 / L of solution. This is our aim

The given percentage is 0.68 g HNO3/ g solution

multiplying this with density to convert g solution into mL solution and dividing with the molecular weight of HNO3 (63 g/mol) to convert g HNO3 to mol. Therefore we obtain

0.016 mol/ mL or 16.23 mol/ L (M)

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Which of the following elements would you expect to be most reactive, based
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Answer:

C. Lithium

Explanation:

This image describes the trend in reactivity. Group 1 metals are always the most reactive so yeah :)

8 0
3 years ago
During which phase of mitosis does the cell begin to split into two daughter cells
artcher [175]

Answer:

\text{Telophase}

Explanation:

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2 years ago
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Sodium has______ Valence electrons and bismuth has ________ electrons
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Sodium has 1 valence electron and bismuth has 83 electrons (5 valence electrons)

Explanation:

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3 years ago
Represent the decomposition of aluminum oxide using the same number of atoms of molecules as are
pantera1 [17]

Answer:

Decomposition of aluminium oxide forms  aluminium atoms and  oxygen atoms.

Explanation:

<u>Decomposition reaction:</u>

When a single compound break down into two or more simpler products.

For example "AB" reactant undergoes decomposition to form "A" and "B" products.

The chemical reaction is as follows.

AB\rightarrow A+B

The given compound is aluminium oxide.

The decomposition reaction of aluminium oxide is a follows.

Al_{2}O_{3}\rightarrow Al+O_{2}

The balanced equation is as follows.

2Al_{2}O_{3}\rightarrow 4Al+3O_{2}

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4 0
3 years ago
Titanium metal is used as a structural material in many high-tech applications such as in jet engines.
Elza [17]

Answer:

a.Cp=0.523

b.Cp=25.02\frac{J}{mol^\circ C}

Explanation:

a. First, we solve the specific heat equation as follows:

Q=mCp\Delta T\\Cp=\frac{Q}{m\Delta T}\\Cp=\frac{89.7J}{33.0g\times5.20^\circ C}=0.523

b. Then, we use the molar mass of titanium to determine its molar heat capacity, as follows:

Cp=0.523\frac{J}{g^\circ C}\times 47.87\frac{g}{mol}\\Cp=25.02\frac{J}{mol^\circ C}

3 0
3 years ago
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