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ziro4ka [17]
4 years ago
6

Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of

such a sample of the acid if the density of the solution is 1.504 g/ml?
Chemistry
1 answer:
dsp734 years ago
6 0
The first thing we need to do here is to recognize the unit of molarity and the units of the given percentage of nitric acid.

Molarity is mol HNO3 / L of solution. This is our aim

The given percentage is 0.68 g HNO3/ g solution

multiplying this with density to convert g solution into mL solution and dividing with the molecular weight of HNO3 (63 g/mol) to convert g HNO3 to mol. Therefore we obtain

0.016 mol/ mL or 16.23 mol/ L (M)

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Balance this equation. If a coefficient of "1" is required, choose "blank" for that box.
Kitty [74]

Answer: 2 C2H4 + 6 O2 => 4 CO2 + 4 H2O

Explanation:The coefficient are as follows: 2: 6: 4: 4

Each atom on the reactant and product side are equal.

Reactant Product

C 2x2 = 4 4x1 = 4

H 2x4 = 8 4x2 = 8

O 6x2 = 12 (4x2) + 4 = 12

7 0
3 years ago
what is the pH of a solution prepared from solid, neutral 2-nitrophenol providing a fromal concentration of 0.0353M, given that
REY [17]

Answer:

pH = 4.34

Explanation:

pH= -1/2(logKa) -1/2(log C)

= -1/2( log 5.98*10^-8) -1/2(log 0.0353)

=-1/2(-7.22)-1/2(-1.45)

=3.61+0.725= 4.34

7 0
3 years ago
What is the volume in mL of a cube with each side 80mm long ?
dem82 [27]
<h3>Answer:</h3>

512 mL

<h3>Explanation:</h3>

We are given;

  • A cube with a side 80 mm long or 8 cm long  

We are required to calculate the volume;

  • Volume refers to the amount of space an object occupies.
  • To calculate the volume of a cube we get the cube of its side;
  • That is, volume of the cube = l³

Therefore;

Volume = (8 cm)³

            = 512 cm³

But; 1 cm³ = 1 mL

Therefore, the volume of the cube in mL is 512 mL

5 0
3 years ago
Read 2 more answers
What are the elements in group two called
mina [271]

Answer: Alkaline-earth metal, any of the six chemical elements that comprise Group 2 (IIa) of the periodic table. The elements are beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). Hopefully i helped

Explanation:

7 0
3 years ago
Read 2 more answers
PLEASE ANSWER, I WILL GIVE BRAINLIEST AND THANKS!
zheka24 [161]

Answer:

Mass  = 8 g

Explanation:

Given data:

Mass of MgO formed  = 20 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

2Mg + O₂     →    2MgO

Number of moles of MgO:

Number of moles = mass/molar mass

Number of moles = 20 g/ 40 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of MgO and O₂ from balance chemical equation:

                     MgO         :            O₂

                        2            :            1

                      0.5          :        1/2×0.5 = 0.25 mol

Mass of oxygen required:

Mass = number of moles × molar mass

Molar mass of O₂  is 32 g/mol

Mass = 0.25 mol × 32 g/mol

Mass = 8 g

4 0
4 years ago
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