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gtnhenbr [62]
3 years ago
8

Please answer asap! worth 35 points!

Chemistry
1 answer:
Gnesinka [82]3 years ago
3 0

Answer:

The enthalpy of the solution is -35.9 kJ/mol

Explanation:

<u>Step 1:</u> Data given

Mass of lithiumchloride = 3.00 grams

Volume of water = 100 mL

Change in temperature = 6.09 °C

<u>Step 2:</u> Calculate mass of water

Mass of water = 1g/mL * 100 mL = 100 grams

<u>Step 3:</u> Calculate heat

q = m*c*ΔT

with m = the mass of water = 100 grams

with c = the heat capacity = 4.184 J/g°C

with ΔT = the chgange in temperature = 6.09 °C

q = 100 grams * 4.184 J/g°C * 6.09 °C

q =2548.1 J

<u>Step 4:</u> Calculate moles lithiumchloride

Moles LiCl = mass LiCl / Molar mass LiCl

Moles LiCl = 3 grams / 42.394 g/mol

Moles LiCl = 0.071 moles

<u>Step 5:</u> Calculate enthalpy of solution

ΔH = 2548.1 J /0.071 moles

ΔH = 35888.7 J/mol = 35.9 kJ/mol (negative because it's exothermic)

The enthalpy of the solution is -35.9 kJ/mol

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Explanation:

According to the mole concept, there are 6.022 \times 10^{23} atoms present in 1 mole of a substance.

In a molecule of CO_{2} there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of CO_{2} are as follows.

1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}

Thus, we can conclude that there are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

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2 years ago
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When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati
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Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}

Here, number of atoms on reactant side are as follows.

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  • O = 2
  • H = 1
  • Cl = 1

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 1
  • H = 2
  • Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply H_{2}O by 2 on product side. Therefore, the equation can be rewritten as follows.

MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}

Hence, number of atoms on reactant side are as follows.

  • Mn = 1
  • O = 2
  • H = 4
  • Cl = 4

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 2
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Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

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