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nikklg [1K]
3 years ago
15

What mass of magnesium hydroxide is required to create a 441 mL solution with a pH of 12.52?

Chemistry
1 answer:
marshall27 [118]3 years ago
4 0

Answer:

0.423g

Explanation:

akording to mass = concetration x volume

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Which of the following are compounds (select all that apply)
olga2289 [7]

Answer:

KNO2, KBr

Explanation:

Chemical compounds are any substance composed of identical molecules consisting of atoms of two or more chemical elements. So NO2 and KBr are compounds, Br2 and Fe are not.

3 0
2 years ago
25.0 cm3 of a solution of sodium hydroxide required 18.8 cm3 of 0.0500 mol/dm3 H2SO4
marshall27 [118]

Answer:

i think so

Ba(OH)2 + H2SO4 ------> BaSO4 + 2H2O

1) Moles of Ba(OH)2 = moles of H2SO4 = 0.025L x 2)0.02M = 5.0 x 10^-4M

Concn of Ba(OH)2 in g/L = 5.0 x 10^-4M x 171.33g/mol = 0.086g/mol

7 0
3 years ago
F
kobusy [5.1K]

Answer:

From the periodic table, Atomic number of fluorine is 7 and atomic mass is 19

8 0
3 years ago
Why compounds with weak molecular forces are usually gases.
mihalych1998 [28]

Answer:

Intermolecular forces are much weaker than the strong covalent bonds within the molecules. ... Very little energy is needed to overcome the intermolecular forces, so simple molecular substances usually have low melting and boiling points. They are often liquids or gases at room temperature

8 0
2 years ago
Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
shutvik [7]

Answer:

  • <u>79%</u>

Explanation:

<u>1) Balanced chemical equation:</u>

  • 2S + 3O₂ → 2SO₃

<u>2) Mole ratio:</u>

  • 2 mol S : 3 mol O₂ : 2 mol SO₃

<u>3) Limiting reactant:</u>

  • Number of moles of O₂

        n = 6.0 g / 32.0 g/mol = 0.1875 mol O₂

  • Number of moles of S:

         n = 7.0 g / 32.065 g/mol = 0.2183 mol S

  • Ratios:

        Actual ratio: 0.1875 mol O₂ / 0.2183 mol S =0.859

        Theoretical ratio: 3 mol O₂ / 2 mol S = 1.5

Since there is a smaller proportion of O₂ (0.859) than the theoretical ratio (1.5), O₂ will be used before all S be consumed, and O₂ is the limiting reactant.

<u>4) Calcuate theoretical yield (using the limiting reactant):</u>

  • 0.1875 mol O₂ / x = 3 mol O₂ / 2 mol SO₃

  • x = 0.1875 × 2 / 3 mol SO₃ =  0.125 mol SO₃

<u>5) Yield in grams:</u>

  • mass = number of moles × molar mass = 0.125 mol × 80.06 g/mol =  10.0 g

<u>6) </u><em><u>Percent yield:</u></em>

  • Percent yield, % = (actual yield / theoretical yield) × 100
  • % = (7.9 g / 10.0 g) × 100 = 79%
6 0
3 years ago
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