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Scilla [17]
4 years ago
12

Explain why unboiled water can be used to prepare an acetic acid solution, but not a naoh solution?

Chemistry
1 answer:
shtirl [24]4 years ago
8 0
NaOH is a hygroscopic compound, which means that it has a very strong affinity for water. Moreover, NaOH is also a stronger base than acetic acid is a strong acid. These two properties of NaOH make it necessary for different precautions to be taken while preparing a solution. 
On the other hand, acetic acid is not very reactive and may easily be prepared in a solution of unboiled water.
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Explanation:

The given data is as follows.

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(a)  Formula to calculate hydraulic radius (r_{H}) is as follows.

              r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}

                          = \frac{2 \times 1}{2(1) + 2(2)}

                          = \frac{1}{3} ft

Formula for equivalent diameter is as follows.

                     D_{eq} = 4 \times r_{H}

                                    = 4 \times \frac{1}{3} ft  

                                    = \frac{4}{3} ft

(b)    Formula for velocity floe is as follows.

                         Q = VA

                     V = \frac{Q}{A}

                        = \frac{48000}{2 \times 1} ft/min

                        = 24000 ft/min

(c)   Formula to calculate Reynold's number is as follows.

         R_{e} = \frac{D \times V \times \rho}{\mu}

                   = \frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}  (as \rho = 0.0744 lb/ft^{3} and \mu = 0.0443 lb/ft. hr)

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As 1 hr = 10 min. So, 53742.66 hr/min \times \frac{60 min}{1 hr}

                            = 3224559.6

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              \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

Putting the given values into the above formula as follows.

               \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

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                      = 6.238 lb/ft^{2}

5 0
4 years ago
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