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klio [65]
3 years ago
5

Mary lost 30 lbs. Before her diet she weighed 180 pounds. What is the percent of change?​

Mathematics
2 answers:
Anestetic [448]3 years ago
7 0

Answer:

The percent change is 16.67

Step-by-step explanation:

liq [111]3 years ago
7 0

Answer:

16.7%

Step-by-step explanation:

Her weight decreased by 30 lb.

Expressed as a fraction:  (-30 lb)/(180 lb) = (-1/6)

As a percentage, her weight loss came to (-1/6)(100%) = 16.7%

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A, b, and c are polynomials, where a = n, b = 2n 6, and c = n2 – 1. what is ab – c in simplest form? –n2 3n 5 n2 6n 1 2n2 6n – 1
Elena L [17]

The equations a = n, b = 2n + 6 and c = n² - 1 are polynomials, and the expression for ab - c is n² + 6n + 1

<h3>How to determine the expression for ab - c?</h3>

The polynomials are given as:

a = n

b = 2n + 6

c = n² - 1

The expression ab - c is calculated using:

ab - c = n * (2n + 6) - (n² - 1)

Expand

ab - c = 2n² + 6n - n² + 1

Collect like terms

ab - c = 2n² - n² + 6n  + 1

Evaluate

ab - c = n² + 6n + 1

Hence, the expression for ab - c is n² + 6n + 1

Read more about polynomials at:

brainly.com/question/4142886

#SPJ4

8 0
2 years ago
Solve 0.9(x-20)=830
Dmitry [639]

Answer:

942.22

Step-by-step explanation:

0.9(x-20)=830

Distribute .9

.9x -18 =830

Add 18 to each side

.9x -18+18=830+18

.9x = 848

Divide each side by .9

.9x/.9 = 848/.9

x =942.22222222

To the nearest hundredth

942.22

7 0
3 years ago
A researcher selects a random sample of size n from a population and uses the collected data to compute a 95% confidence interva
Karo-lina-s [1.5K]

Answer:

I wish I know the answer

Step-by-step explanation:

lemme try again

7 0
2 years ago
Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th
trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

    t = 20: 999 fishes

    t = 30: 1168 fishes

(c)

P(\infty) = 1200

Step-by-step explanation:

Given

P(t) =\frac{d}{1+ke^-{ct}}

d = 1200\\k = 11\\c=0.2

Solving (a): Fishes at t = 0

This gives:

P(0) =\frac{1200}{1+11*e^-{0.2*0}}

P(0) =\frac{1200}{1+11*e^-{0}}

P(0) =\frac{1200}{1+11*1}

P(0) =\frac{1200}{1+11}

P(0) =\frac{1200}{12}

P(0) = 100

Solving (a): Fishes at t = 10, 20, 30

t = 10

P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483

t = 20

P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999

t = 30

P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168

Solving (c): \lim_{t \to \infty} P(t)

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of e^{-ct} decreases

This implies that:

{t \to \infty} = {e^{-ct} \to 0}

So:

The value of P(t) for large values is:

P(\infty) = \frac{1200}{1 + 11 * 0}

P(\infty) = \frac{1200}{1 + 0}

P(\infty) = \frac{1200}{1}

P(\infty) = 1200

5 0
2 years ago
Can someone please check if this is correct?
Solnce55 [7]

Answer:

Just two corrections!  See attached image.

Step-by-step explanation:

The product of 8 and b taken <u>from</u> 10 means begin with 10 and subtract 8b from it.

8 times the difference of 10 and b means find 10 - b first, <u>then</u> multiply by 8.

7 0
2 years ago
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