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3 years ago

Mary lost 30 lbs. Before her diet she weighed 180 pounds. What is the percent of change?

Mathematics

2 answers:

Anestetic [448]3 years ago

7 0

Answer:

The percent change is 16.67

Step-by-step explanation:

liq [111]3 years ago

7 0

Answer:

16.7%

Step-by-step explanation:

Her weight decreased by 30 lb.

Expressed as a fraction: (-30 lb)/(180 lb) = (-1/6)

As a percentage, her weight loss came to (-1/6)(100%) = 16.7%

Read more about polynomials at:

brainly.com/question/4142886

#SPJ4

8 0

2 years ago

Solve 0.9(x-20)=830

Dmitry [639]

Answer:

942.22

Step-by-step explanation:

0.9(x-20)=830

Distribute .9

.9x -18 =830

Add 18 to each side

.9x -18+18=830+18

.9x = 848

Divide each side by .9

.9x/.9 = 848/.9

x =942.22222222

To the nearest hundredth

942.22

7 0

3 years ago

A researcher selects a random sample of size n from a population and uses the collected data to compute a 95% confidence interva

Karo-lina-s [1.5K]

Answer:

I wish I know the answer

Step-by-step explanation:

lemme try again

7 0

2 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago

Can someone please check if this is correct?

Solnce55 [7]

Answer:

Just two corrections! See attached image.

Step-by-step explanation:

The product of 8 and b taken <u>from</u> 10 means begin with 10 and subtract 8b from it.

8 times the difference of 10 and b means find 10 - b first, <u>then</u> multiply by 8.

7 0

2 years ago

Mary lost 30 lbs. Before her diet she weighed 180 pounds. What is the percent of change?​

Mary lost 30 lbs. Before her diet she weighed 180 pounds. What is the percent of change?