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Fed [463]
3 years ago
9

Consider this reaction:

Chemistry
1 answer:
belka [17]3 years ago
8 0

Answer:

C_{HI}=0.164M

Explanation:

Hello,

In this case, based on the given units of the rate constant, it is a first-order reaction with respect to HI, therefore, the rate law is:

\frac{dC_{HI}}{dt} =-kC_{HI}

Whose integration turns out:

ln(C_{HI})=ln(C_{HI}^0)-kt\\C_{HI}=C_{HI}^0exp(-kt)

Therefore, the concentration of HI after 800 second finally result:

C_{HI}=0.330Mexp(-8.74x10^{-4}s^{-1}*800s)\\C_{HI}=0.164M

Best regards.

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What's the IUPAC name pf this compound? CH3-CH-CH2-CH-CHO | | CH3 CL
Svetradugi [14.3K]

Answer:

2-chloro-4-methylpentanal.

Explanation:

Hello there!

In this case, according to the chemical compound:

CH3-CH-CH2-CH-CHO

          |              |

        CH3        Cl

We can see the main functional group is an starting carbonyl, which means this is an aldehyde. Moreover, we can see a Cl-substituent on the second carbon and a methyl substituent on the fourth carbon. Therefore, the IUPAC name turns out: 2-chloro-4-methylpentanal.

Best regards!

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