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2 years ago

3. the [OH-] of a solution with a [H+] of 9.3 x 10^-4 M

Chemistry

1 answer:

Ostrovityanka [42]2 years ago

3 0

Answer:

[OH-] = 1.08x10^-11 M

Explanation:

From the question given,

Concentration of Hydrogen ion, [H+]

= 9.3x10^-4 M

Concentration of Hydroxide ion, [OH-] =..?

The concentration of the hydrogen ion, [H+] and hydroxide ion, [OH-] are related with the following formula:

[H+] x [OH-] = 1x10^-14

Using the above formula, we can easily calculate the concentration of the hydroxide ion, [OH-] as follow:

[H+] x [OH-] = 1x10^-14

[H+] = 9.3x10^-4 M

9.3x10^-4 x [OH-] = 1x10^-14

Divide both side by 9.3x10^-4

[OH-] = 1x10^-14 /9.3x10^-4

[OH-] = 1.08x10^-11 M

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What mass of C6H8O7 should be used every 7.0 X 10^2mg NaHCO3

Savatey [412]

Mass C₆H₈O₇ : 0.531484 g

<h3>Further explanation</h3>

Reaction

3NaHCO₃ (aq) + C₆H₈O₇ (aq) → 3 CO₂ (g) + 3 H₂O (l) + Na₃C₆H₅O₇ (aq)

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2 years ago

0.00000000082 - scientific notation

Nadusha1986 [10]

Answer:

8.2 x 106^-11

Explanation:

To begin this problem you must remember the basic rule of scientific notation, which is, must be between 1-10. .000000000082 is much smaller than 1. However by moving the decimal 11 spots to the right, we can make it 8.2

Continue to move the decimal to the right until the value is in the 1-10 range. Make sure to count the moves to the right.

Once the decimal is in the right spot count the spots moved.

Since the number is wayyy smaller than the answer given the number will be negative 10^-11, in order to make it what is was before.

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2 years ago

How many molecules in each sample? 64.7 g N2 83 g CCl4 19 g C6H12O6

lilavasa [31]

Answer:

1.39x10²⁴ molecules N₂

.25x10²³ molecules CCl₄

6.38x10²² molecules C₆H₁₂O₆

Explanation:

First we convert the given masses into moles, using the compounds' respective molar mass:

64.7 g N₂ ÷ 28 g/mol = 2.31 mol N₂

83 g CCl₄ ÷ 153.82 g/mol = 0.540 mol CCl₄

19 g C₆H₁₂O₆ ÷ 180 g/mol = 0.106 mol C₆H₁₂O₆

Then we multiply each amount by Avogadro's number, to calculate the number of molecules:

2.31 mol N₂ * 6.023x10²³ molecules/mol = 1.39x10²⁴ molecules

0.540 mol CCl₄ * 6.023x10²³ molecules/mol = 3.25x10²³ molecules

0.106 mol C₆H₁₂O₆ * 6.023x10²³ molecules/mol = 6.38x10²² molecules

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