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statuscvo [17]
4 years ago
7

Which particle does the red ball at position #2 represent

Physics
2 answers:
Scorpion4ik [409]4 years ago
6 0
That represents a proton!
jarptica [38.1K]4 years ago
6 0

Answer:

a. proton

B. Proton

C.proton.

D.protin

Explanation:

because if you get it wrong the next you see the next questions its the same but eh answer is in the wong spot.

You might be interested in
You are called as an expert witness to analyze the following auto accident: Car B, of mass 2100 kg, was stopped at a red light w
Artemon [7]

Answer:

Explanation:

Force of friction at car B ( break was applied by car B ) =μ mg = .65 x  2100 X 9.8  = 13377 N .

work done by friction = 13377 x 7.30 = 97652.1 J

If v be the common velocity of both the cars after collision

kinetic energy of both the cars = 1/2 ( 2100 + 1500 ) x v²

= 1800 v²

so , applying work - energy theory ,

1800 v² = 97652.1

v² = 54.25

v = 7.365 m /s

This is the common velocity of both the cars .

To know the speed of car A , we shall apply law of conservation of momentum  .Let the speed of car A before collision be v₁ .

So , momentum before collision = momentum after collision of both the cars

1500 x v₁ = ( 1500 + 2100 ) x 7.365

v₁ = 17.676 m /s

= 63.63 mph .

( b )

yes Car A was crossing speed limit by a difference of

63.63 - 35 = 28.63 mph.

7 0
3 years ago
A student whirls a rubber stopper attached to a string in a horizontal circle above her head. If the radius of the stopper in ci
algol13

Answer:

v = 12.57 m/s

Explanation:

As we know that the radius of the circular motion is given as

R = 50.00 cm

time period of the motion is given as

T = 0.2500 s

now we know that it is moving with uniform speed

so it is given as

v = \frac{2\pi R}{T}

now plug in all data

v = \frac{2\pi(0.50)}{0.25}

v = 12.57 m/s

7 0
3 years ago
Which of the following is not a function of a simple machine?
Airida [17]
A. Increase Energy because simple machines are supposed to help humans use less energy and less force when doing a task that normally requires a lot of force and energy
8 0
3 years ago
Read 2 more answers
A block of 250-mm length and 48 × 40-mm cross section is to support a centric compressive load P. The material to be used is a b
Marrrta [24]

Answer:

153.6 kN

Explanation:

The elastic constant k of the block is

k = E * A/l

k = 95*10^9 * 0.048*0.04/0.25 = 729.6 MN/m

0.12% of the original length is:

0.0012 * 0.25 m = 0.0003  m

Hooke's law:

F = x * k

Where x is the change in length

F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)

The compressive load will generate a stress of

σ = F / A

F = σ * A

F = 80*10^6 * 0.048 * 0.04 = 153.6 kN

The smallest admisible load is 153.6 kN

8 0
3 years ago
A 62kg box is lifted 12 meters off the ground. How much work is done?
Temka [501]

Answer: 7291.2 joules

Explanation:

Work is done when force is applied on an object over a distance.

Thus, Workdone = Force X distance

Since Distance moved by box = 12 metres

mass of box = 62kg

Acceleration due to gravity when box was lifted is represented by g = 9.8m/s^2

Recall that Force = Mass x acceleration due to gravity

i.e Force = 62kg x 9.8m/s^2

= 607.6 Newton

So, Workdone = Force X Distance

Workdone = 607.6 Newton X 12 metres

Workdone = 7291.2 joules

Thus, 7291.2 joules of work was done.

4 0
3 years ago
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