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Kruka [31]
3 years ago
5

A car applies it’s brakes as it approaches a stop sign, slowing he car down is this unbalanced or balanced

Physics
1 answer:
kondor19780726 [428]3 years ago
4 0

Answer:

balanced

Explanation:

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A racecar driver is driving her car down the drag strip at 120 m/s. What is the shortest distance in which she can brake and sto
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Answer:

1034.78 m

Explanation:

The shortest distance is the displacement of the car from initial position to final position.

Displacement of body is given using Newton's equations of motion.

Given:

Initial velocity, u = 120 m/s

Final velocity, v = 0 m/s( As the car stops in its final position)

Coefficient of static friction, \mu=0.71

Acceleration due to gravity, g=9.8\textrm{ } m/s^{2}

Now, when brakes are applied, only friction acts on the body in a direction opposite to that of its motion.

The acceleration of the car when friction acts the stopping force is given as:

a=- \mu g.

The acceleration is negative as it reduces the velocity of the motion and acts in the direction opposite to that of the motion.

Plug in 0.71 for \mu and 9.8 m/s² for g. Solve for a.

So, a=-0.71\times 9.8=-6.958\textrm{ }m/s^{2}.

Now, displacement of the car is given using the following equation of motion:

v^{2}=u^{2} +2aS

Here, S is the displacement of the racing car.

Plug in 120 m/s for u, 0 m/s for v, -6.958 m/s² for a. Solve for S. This gives,

0^{2} =(120)^{2}+2(-6.958)S\\13.916S=14400\\S=\frac{14400}{13.916}=1034.78\textrm{ m}

Therefore, the shortest distance in which she can brake and stop is 1034.78 m.

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