Answer:
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The average time that it takes for the car to travel the first 0.25m is 2.23 s
The average time that it takes for the car to travel the first 0.25 m is given by:

The average time to travel just between 0.25 m and 0.50 m is 0.90 s
First of all, we need to calculate the time the car takes in each trial to travel between 0.25 m and 0.50 m:

Then, the average time can be calculated as

Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s
The velocity of the car while travelling the second 0.25 m section is equal to the distance covered (0.25 m) divided by the average time (0.90 s):

Answer:
x ’= 368.61 m, y ’= 258.11 m
Explanation:
To solve this problem we must find the projections of the point on the new vectors of the rotated system θ = 35º
x’= R cos 35
y’= R sin 35
The modulus vector can be found using the Pythagorean theorem
R² = x² + y²
R = 450 m
we calculate
x ’= 450 cos 35
x ’= 368.61 m
y ’= 450 sin 35
y ’= 258.11 m
T<span>he relationship between wavelength and frequency is inverse.
This is as the wavelength increases the frequency decreases and as the wavelength decreases the frequency increases.
The light meets this equation that reflects the relationship between wavelength and frequency:
c = wavelength * frequency => wavelength = c / frequency
where c is the constant speed of light.
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Answer:
Work done, W = 10195.92 Joules
Explanation:
Given that,
Mass of the crate, m = 170 kg
Distance, d = 10.2 m
The coefficient of friction, 
Let W is the work done by the mover. It is given by in terms of coefficient of friction as :


W = 10195.92 Joules
So, the work done by the mover is 10195.92 Joules. Hence, this is the required solution.