A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled

Question

3 years ago

15

A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled

2.0 × 10 7 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour?

Physics

2 answers:

jek_recluse [69] · Answer 1 · 2022-02-25T03:05:28+03:00

jek_recluse [69]3 years ago

7 0

Answer:

the correct answer is 2.66 x 10^-4

Explanation:

dmitriy555 [2] · Answer 2 · 2022-02-25T00:40:17+03:00

You haven't described the shape of the orbit.
Fortunately, it doesn't matter.

Average speed = (distance covered) / (time to cover the distance)

   = (2.0 x 10⁷ meters) / (1 hour)

   =   2.0 x 10⁷ meters/hour

   =   5,555 and 5/9 meters/second .

Note that this is the satellite's speed.

Regarding velocity:

   Velocity = (displacement) / (time for the displacement)

   = 10 meters/hour

   = 0.002777... meters/second (rounded)

   in the direction from the starting point
   to the location after that one hour.