Answer:
(a) The angle of projection is 63 degree.
(b) The velocity of projection is 24.5 m/s.
Explanation:
Height, h = 1 m
horizontal distance, d = 50 m
time, t = 4.5 s
Let the initial velocity is u and the angle is A.
(a) Horizontal distance = horizontal velocity x time
50 = u cos A x 4.5
u cos A = 11.1 .....(1)
Use second equation of motion in vertical direction
Divide (2) by (1)
tan A = 1.97
A = 63 degree
(b) Substitute the value of A in equation (2)
u x sin 63 = 21.8
u = 24.5 m/s
Answer:
The energy absorbed by the atomic electrons in the mercury atom is J
Explanation:
Given:
Potential V
According to the conservation law,
Loss in kinetic energy = Gain in potential energy
Here, energy absorbed by the atomic electrons is given by,
Where ( charge of electron )
J
Therefore, the energy absorbed by the atomic electrons in the mercury atom is J
The value of the force, F₀, at equilibrium is equal to the horizontal
component of the tension in string 2.
Response:
Given:
The weight of the rod = The sum of the vertical forces in the strings
Therefore;
M·g = T₂·cos(37°) + T₁
The weight of the rod is at the middle.
Taking moment about point (2) gives;
M·g × L = T₁ × 2·L
Therefore;
Which gives;
F₀ = T₂·sin(37°)
Which gives;
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