You and a friend try to move a 50.0 kg box over a smooth floor (no friction). You push down and right with a force 30.0 N, at an
gle of 20 degrees below the horizontal. Your friend ties a rope to the front of the box and pulls with a 25.0 N force, at an angle 30 degrees above the horizontal. What is the acceleration of the box in the horizontal direction? Assuming the box does not move in the vertical direction, what is the normal force on the box?
1 answer:
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Answer:
5365 N
Explanation:
v = Final velocity = 23 m/s
u = Initial velocity = -14 m/s (opposite direction)
m = Mass of ball = 145 g
t = Time taken = 1 ms
Impulse is given by
Impulse is also given by
The magnitude of the average force exerted by the bat on the ball is 5365 N
The speed of an object in a mass-spring system is given under the function
Here,
m = mass
k = Spring constant
A = Amplitude
x = Position
When the position is at the equilibrium point (x = 0), the speed will be maximum, and could even be expressed as
So the correct answer is B.