Can someone help me with this problem please?

Could yall help please

ser-zykov [4K]

Answer:

C

Step-by-step explanation:

As you know, 390% is 3.9. You multiply 3.9*30 and get 117 or something. That rounds to about 120, so C.

I hoped that helped

6 0

3 years ago

Suppose that a sample of size 100 is to be drawn from a population with standard deviation L0. a. What is the probability that t

NARA [144]

Answer:

The probability that the sample mean will lie within 2 values of μ is 0.9544.

Step-by-step explanation:

Here

the sample size is given as 100
the standard deviation is 10

The probability that the sample mean lies with 2 of the value of μ is given as

$P(| \bar{X}-\mu|$

Here converting the values in z form gives

$P(-2$

Substituting values

$P(-2$

From z table

$P(z\leq 2)=0.9772\\P(z\leq -2)=0.0228\\P(-2\leq z\leq 2)=P(z\leq 2)-P(z\leq -2)\\P(-2\leq z\leq 2)=0.9772-0.0228\\P(-2\leq z\leq 2)=0.9544\\$

So the probability that the sample mean will lie within 2 values of μ is 0.9544.

5 0

3 years ago

Simplify 2(a-3)/(a-4)(a-5)+(a-1)/(3-a)(a-4)+(a-2)/(5-a)(a-3)

Umnica [9.8K]

Answer:

$\dfrac{5}{x^3-12x^2+47x-60}$

Step-by-step explanation:

Though it is not what you have written, we think you want to simplify ...

$\dfrac{2(a-3)}{(a-4)(a-5)}+\dfrac{(a-1)}{(3-a)(a-4)}+\dfrac{(a-2)}{(5-a)(a-3)}\\\\=\dfrac{2(a-3)^2}{(a-3)(a-4)(a-5)}+\dfrac{-(a-1)(a-5)}{(a-3)(a-4)(a-5)}+\dfrac{-(a-2)(a-4)}{(a-3)(a-4)(a-5)}\\\\=\dfrac{2(a^2-6a+9)-(a^2-6a+5)-(a^2-6a+8)}{x^3-12x^2+47x-60}\\\\=\boxed{\dfrac{5}{x^3-12x^2+47x-60}}$

_____

When writing a fraction in plain text, parentheses are needed around the entire denominator. The order of operations tells you that a/bc = (a/b)c, not a/(bc).

6 0

3 years ago

100 POINTS HELP ASAP Linear Combination

notka56 [123]

Answer:

1) $x=\dfrac12$

2) $n = -3 \ \ \textsf{and} \ \ m = -4$

3) see below

4) A: 0 = 1

Step-by-step explanation:

Question 1

$15-0.5(4x-2)+4x=17$

$\implies 15-2x+1+4x=17$

$\implies 2x+16=17$

$\implies 2x=1$

$\implies x=\dfrac12$

Question 2

$\textsf{rearrange} \ n=m+1 :$

$\implies -m=-n+1$

$\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\$

$\implies0=n+3$

$\implies n=-3$

$\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:$

$\implies m=-3-1$

$\implies m=-4$

Question 3

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

Question 4

$3j=k$

$k=3j+1$

$\textsf{rearrange} \ 3j=k :$

$\implies -k=-3j$

$\textsf{add equations}\ -k=-3j \ \ \textsf{and}\ \ k=3j+1:$

$\implies 0=1$

Solution = A

6 0

3 years ago

The sales team at an electronics store sold 48 computers last month. The manager at the store wants to encourage the sales team

brilliants [131]

The number of computers sold has to be 30% more than 48.
30% of 48 plus the numbers sold last month
.3 x 48 +48
14.4 +48
62.4
Round up because the numbers has to be an integer value. (You can't have 2/5 of a computer).

63 computers

Hope this helps :)

8 0

3 years ago

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