The pressure of a gas is 750 torr when its volume is 400. ml. Calculate the

Chemistry

1 answer:

ololo11 [35]3 years ago

7 0

Answer:

a. 0.66 atm

Explanation:

Pi = 750 torr = 0.99 atm. Pf = ?

Vi = 400 ml Vf = 600ml

Using PiVi = PfVf

Then 400ml × 0.99atm = Pfatm × 600ml

Solving for Pf, we have,

Pf = (400ml × 0.99atm)/600ml

Pf = 0.66atm

You might be interested in

Which group are most stars found in

Luden [163]

Answer:

The White Dwarfs are very hot stars, which are small in size and relatively dim. They are found in the lower left of the H-R Diagram. The Main Sequence is a band of stars, which includes most of the stars, like our Sun. These are usually smaller stars, often dwarf stars.

Explanation:

3 0

3 years ago

Read 2 more answers

Consider the balanced chemical equation below.

viktelen [127]

Explanation:

$here \: is \: your \: explanation : - \\ \\ given \: balanced \:equation \: = > \\ \\ 2 A=>C \: + \: 4D \\ \\ by \: this \: equation \: we \: get \: \\ \\ 2 \: moles \: of \: A \: produce \: 4 \: moles \: \\ \\ of \: D \\ \\ hence \: . \: 1 \: mole \: can \: produce \: = 4 \div 2 \\ \\ = > 2 \: moles \: \\ \\ so \: if \: 6 \: moles \: of \: A \: used \: then \: \\ \\ amount \: of \: D \: produced \: = (6 \times 2) \\ \\ = > 12 \: moles \: of \: D \\ \\ \mathcal\blue{ Hope \: it \: helps \: you \: (. ❛ ᴗ ❛.) }$

5 0

3 years ago

A sample of an unknown gas effuses in 14.4 min. An equal volume of H2 in the same apparatus under the same conditions effuses in

Elena-2011 [213]

Answer:- molar mass of the unknown gas is 71.5 gram per mol.

Solution:- From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.

When we compare the effusion rates of two gases then the formula for Graham's law is:

$\frac{rate_1}{rate_2}=\sqrt{\frac{M_2}{M_1}}$

In this formula, V stands for volume and M stands for molar mass

Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:

$\frac{t_2}{t_1}=\sqrt{\frac{M_2}{M_1}}$

let's say in formula, subscript 1 is for hydrogen gas and 2 is for the unknown gas.

Molar mass of hydrogen is 2.02 grams per mol and the time taken to effuse it is 2.42 min. The time taken to effuse the unknown gas is 14.4 min and we are asked to calculate it's molar mass. let's plug in the values in the formula:

$\frac{14.4}{2.42}=\sqrt{\frac{M_2}{2.02}}$