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3 years ago

Help Help just answers what ever you think is right but hurry

Physics

1 answer:

Dennis_Churaev [7]3 years ago

4 0

Answer:

it is caused by gases in earths atmosphere. it warms up earhs surface and lower atmosphere.

Explanation:

from what i know, these seem like the only ones that apply.

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If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front o

Svetach [21]

C.
18 / x = 12 / 4
12x = 72
x = 6mm

6 0

3 years ago

Can a average velocity be zero.Why?

marishachu [46]

Answer:

Yes

Explanation:

Average velocity is the ratio of total displacement and time taken for that displacement:

$average \space\ velocity = \frac{displacement}{time}$

This means if displacement is zero, then average velocity will also be zero.

Displacement is zero when an object moves some distance in one direction, and then moves the same distance but in the opposite direction.

∴ As it is possible for displacement to be zero, it is also possible for average velocity to be zero.

4 0

2 years ago

I NEED HELP ASAP IM ON TIMER !!!!!!!!

White raven [17]

Answer:

Explanation:

The average velocity is the ratio of total displacement and time.The average speed is the ratio of total distance and time.Therefore the average speed and average velocity are equal if the total displacement is equal to the total distance that is if the body travels along a straight line without changing the direction.

3 0

2 years ago

Calculate the velocity of a car that travelled 120km in 2 hours

Naddik [55]

I need context poggg

5 0

2 years ago

The elastic energy stored in your tendons can contribute up to 35 % of your energy needs when running. Sports scientists have st

FinnZ [79.3K]

Answer:

Explanation:

From the given information:

The difference in the maximum energy stored is can be determined by finding the difference in the maximum stored energy in the sprinters and that of the non-athlete:

$\Delta U = \dfrac{1}{2}k(x_2^2 - x_1^2)$

$\Delta U = \dfrac{1}{2} (32 \ N/mm) (\dfrac{1 \ mm}{10^{-3} \ m}) ((40\times 10^{-3})^2 - (32\times 10^{-3})^2)$

$\Delta U =16000 \times (5.76\times 10^{-4})$

$\mathbf{\Delta U =9.216\ J}$

8 0

3 years ago