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Thepotemich [5.8K]
3 years ago
8

Please Help for question 3,4,5,6,7

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

3. From the graph, g(0) = -1.

4. t(x) = 2x + 5

   t(0.5) = 2(0.5) + 5 = 1 + 5 = 6

   g(6) = 0 (from graph)

5. 15 = 2x + 5

    2x = 10

      x = 5

6. g(1) = 0

   t(0) = 5

7. t(1) = 7

   g(7) = -2

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Chip and dale are driving in a toy engine around the Christmas tree at a speed of 300 miles/hour. how many minutes will it take
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Using proportions, it is found that it will take them 0.00248548 minutes to do one loop.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, according to their speed, in 60 minutes, they drive 300 miles. In how many minutes will they drive 20 m = 0,0124274 miles?

The <em>rule of three</em> is:

60 min - 300 miles

x min - 0.0124274 miles

Applying cross multiplication:

300x = 60 \times 0.0124274

x = \frac{60 \times 0.0124274}{300}

x = 0.00248548

It will take them 0.00248548 minutes to do one loop.

More can be learned about proportions at brainly.com/question/24372153

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A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
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Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

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2 years ago
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