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Luda [366]
4 years ago
7

A proton enters a constant magnetic field of magnitude 0.050 t and traverses a semicircle of radius 1.0 mm before leaving the fi

eld. what is the proton's speed?
Physics
1 answer:
ElenaW [278]4 years ago
4 0

Velocity of proton= 4782 m/s

Explanation:

For proton, the centripetal force required for circular motion is provided by the magnetic force,

so Fm= Fc

q v B = m v²/r

m= mass of proton

v= velocity

B =magnetic field=0.05 T

q= charge= 1.6 x 10⁻¹⁹

r= radius = 1 mm =0.001 m

v= q B r/m

V= (1.6 x 10⁻¹⁹)(0.05)(0.001)/(1.673 x 10⁻²⁷)

V= 4782 m/s

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Trenches are the deepest part of the oceans, narrow and long depressions on the sea floor. One good example is the Mariana Trench, the deepest part of the ocean

Explanation:

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3 years ago
Explain thermodynamics in how a car runs?
serg [7]

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3 0
3 years ago
A missile is moving 1350 m/s at 25.0° angle. It needs to hit in a 55.0° direction in 10.20 s. What is the direction of its final
77julia77 [94]

Answer:

final velocity = 3504 m/s  

Explanation:

<em>Given data:</em>

velocity of missile = Vi = 1350m/s

angle at which missile is moving = 25degree

distance between missile and targets = 23500m

angle between target and missile=55degree

time=10.2s

<em>To find:</em>

Final velocity: ?

<em>Formula:</em>

x = Vx*t + ½*ax*t²  

Let x be the horizontal component of distance

x = ertical component of distance

t-time

ax = horizontal component of acceleration

ay = Vertical component of acceleration

Vx = horizontal component of velocity

Vy = Vertical component of velocity

<em>Solution:</em>

x = Vx*t + ½*ax*t²

23500m * cos55.0º = 1350m/s * cos25.0º * 10.20s + ½ * ax * (10.20s)²  

ax = 19.2 m/s²  

V'x = Vx + ax*t = 1350m/s * cos25.0º + 19.2m/s² * 10.20s = 1419 m/s  

<em>similarly vertically:</em>

y = Vy*t + ½*ay*t² 

23500m * sin55.0º = 1350m/s * sin25.0º * 10.20s + ½ * ay * (10.20s)²  

ay = 258 m/s²  

V'y = Vy + ay*t

     = 1350m/s * sin25.0º + 258m/s² * 10.20s = 3204 m/s  

V = √(V'x² + V'y²)

   = 3504 m/s  

8 0
3 years ago
Which single force acts on a object in a free fall
11Alexandr11 [23.1K]

Answer:

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4 0
3 years ago
What is the displacement of the object from 12 seconds to 16 seconds
spayn [35]

Answer:

<em>The displacement of the object is -8 m</em>

Explanation:

<u>Displacement</u>

The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.

If the area is below the y-axis, then the displacement is negative. Otherwise is positive.

It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.

From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.

The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:

\displaystyle D = \frac{4*(-4)}{2}=-\frac{16}{2}=-8\ m

The displacement of the object is -8 m

8 0
3 years ago
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