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4 years ago

Which of Newton’s Laws involves mass and acceleration?

Physics

2 answers:

Temka [501]4 years ago

4 0

The answer is <span>Newton’s</span> 2nd law. Thank you!

castortr0y [4]4 years ago

3 0

<span>Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
In short, It's Newton's 2nd law.
Brainliest please if you also found this was correct.
Sources: http://www.physicsclassroom.com/class/newtlaws/Lesson-3/Newton-s-Second-Law
</span>

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A proton that has a mass m and is moving at +164 m/s undergoes a head-on elastic collision with a stationary carbon nucleus of m

Irina18 [472]

The concept of this problem is the Law of Conservation of Momentum. Momentum is the product of mass and velocity. To obey the law, the momentum before and after collision should be equal:

m₁ v₁ + m₂v₂ = m₁v₁' + m₂v₂', where
m₁ and m₂ are the masses of the proton and the carbon nucleus, respectively,
v₁ and v₂ are the velocities of the proton and the carbon nucleus before collision, respectively,
v₁' and v₂' are the velocities of the proton and the carbon nucleus after collision, respectively,

m(164) + 12m(0) = mv₁' + 12mv₂'
164 = v₁' + 12v₂' --> equation 1

The second equation is the coefficient of restitution, e, which is equal to 1 for perfect collision. The equation is

(v₂' - v₁')/(v₁ - v₂) = 1
(v₂' - v₁')/(164 - 0) = 1
v₂' - v₁'=164 ---> equation 2

Solving equations 1 and 2 simultaneously, v₁' = -138.77 m/s and v₂' = +25.23 m/s. This means that after the collision, the proton bounced to the left at 138.77 m/s, while the stationary carbon nucleus move to the right at 25.23 m/s.

7 0

3 years ago

What is 0 point energy times negative 0 point energy ????????

elixir [45]

1 point energy should be the answer

8 0

3 years ago

A number is written in scientific notation when it is the product of a number less than 10 but greater than or equal to 1 and a

Bess [88]

Answer:

$Mass = 1.99 * 10^{30} kg$

Explanation:

Given

$Mass = 1,990,000,000,000,000,000,000,000,000,000\ kg$

Required

Rewrite using scientific notation

The format of a number in scientific notation is

$Digit = a * 10^n$

Where $1 \geq\ a\geq\ 10$

So the given parameter can be rewritten as

$Mass = 1.99 * 1,000,000,000,000,000,000,000,000,000,000\ kg$

Express as a power of 10

$Mass = 1.99 * 10^{30} kg$

Hence, the equivalent of the mass of the sun in scientific notation is:

$Mass = 1.99 * 10^{30} kg$

7 0

3 years ago

When the starter motor on a car is engaged, there is a 320 A current in the wires between the battery and the motor. Suppose the

Salsk061 [2.6K]

Answer:

0.5

Explanation:

because it is V uwbsusvegwjosnfvehdbuxbdusndgdghqbwbwbbeuehdbdhdhdhdudhdhdudhdnskowoqllqlqlqnebe

8 0

3 years ago

A motorboat maintained a constant speed of 15 miles per hour relative to the water in going 10 miles upstream and then returning

Lesechka [4]

Answer:

speed of current is 5 mile/hr

Explanation:

GIVEN DATA:

speed of motorboat = 15 miles/hr relative with water

let c is speed of current

15-c is speed of boat at upstream

15+c is speed of boat at downstream

we know that

travel time=distance/speed

$\frac{10}{15-c} +\frac{10}{15+c} = 1.5$

150+10c+150-10c=1.5(15-c)(15+c)

300=1.5(225-c^2)

300=337.5-1.5c^2

200=225-c^2

c^2=25

c = 5

so speed of current is 5 mile/hr

6 0

3 years ago