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2 years ago

What is the displacement of the object from 12 seconds to 16 seconds

Physics

1 answer:

spayn [35]2 years ago

8 0

Answer:

<em>The displacement of the object is -8 m</em>

Explanation:

<u>Displacement</u>

The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.

If the area is below the y-axis, then the displacement is negative. Otherwise is positive.

It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.

From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.

The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:

$\displaystyle D = \frac{4*(-4)}{2}=-\frac{16}{2}=-8\ m$

The displacement of the object is -8 m

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Electromagnetic waves differ from other types of waves because they are

nikklg [1K]

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3 years ago

A vertical scale on a spring balance reads from 0 to 155 N . The scale has a length of 10.0 cm from the 0 to 155 N reading. A fi

Harrizon [31]

Answer:

mass of the fish is 8.11 kg

Explanation:

As we know that the frequency of oscillation of spring block system is given as

$f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$

here we know that the reading of scale varies from 0 to 155 N from length varies from x = 0 to x = 10 cm

Now we have

$k = \frac{155}{0.10} N/m$

$k = 1550 N/m$

so now we have

$2.20 = \frac{1}{2\pi}\sqrt{\frac{1550}{m}}$

$m = 8.11 kg$

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3 years ago

Why are the element from period 2 grouped together

valentinak56 [21]

All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons. All of the elements in the second row (the second period) have two orbitals for their electrons. As you move down the table, every row adds an orbital.

4 0

3 years ago

"The drawing shows three layers of different materials, with air above and below the layers. The interfaces between the layers a

My name is Ann [436]

Answer:

Angle of incidence that entered material b= 63.1°

Angle of incidence between a and b = 55.9°

Explanation: Using the formular:

n1sintheta1= n2sintheta2

The light ray which enters material B will be

1.4Sin72.8° = 1.5Sin theta

1.3373= 1.5Sintheta

sintheta = 1.3373/1.5

Sin^-1 0.8916 = Theta

63.1 = theta

When the ray hits interface with material a

1.5Sin63.1 = 1.3 Sin theta

1.3374 = 1.3Sin theta

Sintheta= 1.3374/1.3

Sin theta = 1.0877

There will be total reflection off the boundary b c because sin theta exceeded 1 in value.

The equation should be

1.4sin63.1 = 1.4 sin theta

Sin theta=72.8°

When the ray hits air-c boundary:

1.4sin72.8=1.00sin theta

Sin theta=1.3374/1 =1.3374

There is total reflection.

In material a,the ray will:

1.3sin72.8° = 1.00sin theta

There will be total reflection when the ray hits a-b boundary.

1.3sin72.8= 1.5sintheta

Sin theta= 1.2419/ 1.5

Sin theta =0.8279

Theta= Sin^-10.8279= 55.88°

When ray hits c-air boundary

1.4sin63.1= 1.00sintheta

1.2485= sin theta = Toal reflection.

Therefore when the ray of light pass through the layers of material a, b and c the boundary with air on top and bottom will be total reflection.

7 0

3 years ago

What measures the radiation given off by earth

gladu [14]

i thinkits an instrument called seismograph. not sure

3 0

3 years ago