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raketka [301]
3 years ago
12

Explain thermodynamics in how a car runs?

Physics
1 answer:
serg [7]3 years ago
3 0

The Otto Cycle can be used to describe how an internal combustion engine works, which allows your car to run by just filling it up with gas. <span>Each of the numbers shown in the figure (1 through 6) represent one stage of the Otto cycle, or one step of the internal combustion process. The common automobile engine is called a “4 Stroke Engine” because it has 4 strokes, which are the Intake Stroke, Exhaust Stroke, Compression Stroke, and Power Stroke. The “Combustion Process” shown in the Otto Cycle in the figure occurs between Strokes 3 and 4, and the “Heat Rejection” shown in the figurea occurs between Strokes 3 and 4.</span>

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W=∆KE

KE=1/2m∆v^2

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4 years ago
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A light bulb does 100 joules of work in 2.5 seconds. how much work power dos it have
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100/2.5 because power=energy/time
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The Mars Curiosity rover was required to land on the surface of Mars with a velocity of 1 m/s. Given the mass of the landing veh
Aliun [14]

Answer:

The value is      A   = 39315 \  m^2

Explanation:

From the question we are told that

    The velocity which the rover is suppose to land with is  v  =  1 \ m/s

    The  mass of the rover and the parachute is  m  =  2270 \ kg

     The  drag coefficient is  C__{D}}  =  0.5

      The atmospheric density of Earth  is  \rho =  1.2 \  kg/m^3

     The acceleration due to gravity in Mars is  g_m  =  3.689 \  m/s^2

     

Generally the Mars  atmosphere density is mathematically represented as

          \rho_m  =  0.71 *  \rho

=>        \rho_m  =  0.71 *  1.2

=>        \rho_m  = 0.852 \  kg/m^3

Generally the drag force on the rover and the parachute  is mathematically represented as

          F__{D}} =  m  *  g_{m}

=>       F__{D}} =  2270   *  3.689  

=>       F__{D}} =  8374 \ N  

Gnerally this drag force is mathematically represented as

         F__{D}} =   C__{D}} *  A *  \frac{\rho_m * v^2 }{2}

Here A is the frontal area

So  

         A   =  \frac{2 *  F__D }{ C__D}  *  \rho_m  * v^2   }

=>       A   =  \frac{2 * 8374 }{ 0.5 *  0.852    *  1 ^2   }

=>       A   = 39315 \  m^2

8 0
3 years ago
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Answer:

Explanation:

hope this helps!

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.................... protons :)

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