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slavikrds [6]
3 years ago
8

12, The error in measurement may occur due to

Physics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

d, Due to all reasons in a, b and c​

Explanation:

All of the reasons from the choices can lead to errors in measurement. An error is an uncertainty introduced to a scientific process.

Errors can be due to the following reasons;

  • It can be to a poor technician; an inexperienced scientist can introduce serious into their set up. Even when recording their observation, a dearth of experience can lead to error.
  • Faulty apparatus can also lead to errors in measurement. An instrument that is poorly calibrated can also result in measurement errors.
  • An inappropriate scientific method or measuring guidelines can also lead to errors in measurements.
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Identify the kind of simple machine represented by each of these examples: a. A drill bit b. A skateboard ramp c. A boat oar
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Answer:

a skateboard ramp

Explanation:

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Heat moves from hot to cold either through air or liquid <br>​
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both

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How long would it take a machine to do 5.000
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a

Explanation:

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find the mass of a ball on a roof 30 meters high, if the ball's gravitational potential energy is 58.8 joules
Sidana [21]
We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.
3 0
3 years ago
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A string under a tension of 50.4 N is used to whirl a rock in a horizontal circle of radius 2.51 m at a speed of 21.1 m/s. The s
Leokris [45]

Answer:

619.8 N

Explanation:

The tension in the string provides the centripetal force that keeps the rock in circular motion, so we can write:

T=m\frac{v^2}{r}

where

T is the tension

m is the mass of the rock

v is the speed

r is the radius of the circular path

At the beginning,

T = 50.4 N

v = 21.1 m/s

r = 2.51 m

So we can use the equation to find the mass of the rock:

m=\frac{Tr}{v^2}=\frac{(50.4)(2.51)}{21.1^2}=0.284 kg

Later, the radius of the string is decreased to

r' = 1.22 m

While the speed is increased to

v' = 51.6 m/s

Substituting these new data into the equation, we find the tension at which the string breaks:

T'=m\frac{v'^2}{r'}=(0.284)\frac{(51.6)^2}{1.22}=619.8 N

5 0
3 years ago
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