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3 years ago

A student pushes a box with a total mass of 50 kg. What is the net force on the box

Physics

1 answer:

borishaifa [10]3 years ago

8 0

Answer:

75 N

Explanation:

Apply Newton's second law:

∑F = ma

∑F = (50 kg) (1.5 m/s²)

∑F = 75 N

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A car goes round a curve of radius 48m, the road is banked at an angle of 15 with the horizontal,at what maximum speed may the c

Marizza181 [45]

Answer:

11 m/s

Explanation:

Draw a free body diagram. There are two forces acting on the car:

Weigh force mg pulling down

Normal force N pushing perpendicular to the incline

Sum the forces in the +y direction:

∑F = ma

N cos θ − mg = 0

N = mg / cos θ

Sum the forces in the radial (+x) direction:

∑F = ma

N sin θ = m v² / r

Substitute and solve for v:

(mg / cos θ) sin θ = m v² / r

g tan θ = v² / r

v = √(gr tan θ)

Plug in values:

v = √(9.8 m/s² × 48 m × tan 15°)

v = 11.2 m/s

Rounded to 2 significant figures, the maximum speed is 11 m/s.

3 0

3 years ago

The momentum of an object is 35 kg•m/s and it is travelling at a speed of 10 m/s.

Naddik [55]

Answer:

${ \bf{momentum = mass \times velocity}} \\ \\ { \tt{35 = m \times 10}} \\ { \tt{mass = 3.5 \: kg}}$

4 0

2 years ago

Taylor mixes two liquids together in a beaker. A solid forms at the bottom of the beaker, and the liquid changes from pink to bl

Dimas [21]

It is a chemical change and a physical change

3 0

2 years ago

An electric model train is accelerated at a rate of 8 m/s^2 by a 12 N force? What is the

jok3333 [9.3K]

Answer:

m = 1.5 kg

Explanation:

Data:

Aceleration (a) = 8 m/s²
Force (F) = 12 N
Mass (m) = ?

Use formula:

$\boxed{m = \frac{F}{a}}$

Replace in the formula:

$\boxed{m = \frac{12N}{8\frac{m}{s^{2}}}}$

Equate the newtons:

$\boxed{m = \frac{12kg*\frac{m}{s^{2}}}{8\frac{m}{s^{2}}}}$

Simplify m/s²:

$\boxed{m = \frac{12kg}{8}}$

It divides:

$\boxed{m =1.5kg}$

What is the mass of the train?

The mass of the train is 1.5 kilograms.

4 0

2 years ago

A 1232 kg car moving north at 25.6 m/s collides with a 2028 kg car moving north at 17.5 m/s . They stick together. In what direc

Citrus2011 [14]

Answer:

I. Angle = 41.7° Northeast.

II. Vr = 7.08m/s

Explanation:

Let the two cars be denoted by A and B

Given the following data;

Mass of car A = 1232 Kg

Velocity of car A = 25.6 m/s

Mass of car B = 2028 Kg

Velocity of car B = 17.5m/s

First of all, we would solve for momentum;

Momentum = mass × velocity

Momentum, M1 = 1232 × 25.6

Momentum, M1 = 31539.2 Kgm/s

Momentum, M2 = 2028 × 17.5

Momentum, M2 = 35490 Kgm/s

Now, let's find the resultant momentum using the Pythagoras theorem;

R² = M1² + M2²

R² = 31539.2² + 35490²

R² = 994721136.6 + 1259540100

R² = 2254261237

Taking the square root of both sides, we have

Resultant momentum, R = 47479.06 Kgm/s

To find the direction;

Angle = tan¯¹(M1/M2)

Angle = tan¯¹(31539.2/35490)

Angle = tan¯¹(0.89)

Angle = 41.7° Northeast.

To find the speed;

R = (M1 + M2)Vr

47479.06 = (31539.2 + 35490)Vr

47479.06 = 67029.2Vr

Vr = 47479.06/67029.2

Vr = 7.08m/s

6 0

2 years ago