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3 years ago

11

A student pushes a box with a total mass of 50 kg. What is the net force on the box

1 answer:

borishaifa [10]3 years ago

8 0

Answer:

75 N

Explanation:

Apply Newton's second law:

∑F = ma

∑F = (50 kg) (1.5 m/s²)

∑F = 75 N

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What is the velocity of a wave that has a frequency of 400Hz and a wavelength of 0.5 meters

iren2701 [21]

Answer: 12

Explanation:

Let’s take for instance the case of a wave with a frequency of 400 Hz going through a material at a speed of .5 m/s. The wavelength result is 12 m. Wave velocity (m/s) = Frequency (Hz) x Wavelength (m)

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3 years ago

Read 2 more answers

Interactive Solution 11.13 presents a model for solving this problem. A solid concrete block weighs 100 N and is resting on the

mash [69]

Answer:

The value is $} N = 66 \ blocks$

Explanation:

From the question we are told that

The weight of the block is $W_b = 100 \ N$

The dimension of the block is $d = 0.400 m \ X \ 0.250 \ m \ X \ 0.130 \ m$

Generally two atmosphere is equivalent to

$P_{2atm} = 2 * 1.013 *10^{5} = 202600 \ N/m^2$

Generally 1 atm = $1.013 *10^{5} N/m^2$

The area of the block would be evaluated using width and height because we need for the smaller surface to be in contact with the ground in order to maximize the pressure and minimize number of blocks

So

$A = 0.250 * 0.130$

=> $A = 0.0325 \ m^2$

Generally the force due to this blocks is mathematically represented as

$F = N * W_b$

Here N is the number of blocks

So

$} 202600 = \frac{N * 100 }{ 0.0325}$

=> $} N = 66 \ blocks$

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3 years ago

Before CDs and cassette tapes, there were vinyl records. The most comon spun with an angular velocity of 33.3revolutionsperminut

sashaice [31]

Answer:

539.5°

Explanation:

33.3 revolutions per minute

1 revolution = 360°

1 minute = 60 seconds

hence

33.3 revs ----> 1 minute = 60 seconds

X revs -----------> 2.70 seconds

X = (33.3 x 2.7)÷60 = 1.4985 revolutions in 2.70 seconds

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3 years ago

The y component of the electric field of an electromagnetic wave travelling in the +x direction through vacuum obeys the equatio

notsponge [240]

Answer:

λ =8.57 μ m

Explanation:

Given that

Ey = 375 cos [kx − (2.20 × 10¹⁴ rad/s)t] N/C

Standard form

Ey=Eo cos[k x-ωt] N/C

By comparing the given equation with the standard wave equation

Eo = 375 N/C

ω = 2.20 × 10¹⁴ rad/s

We know that ω = 2 π f

$f=\dfrac{\omega}{2\pi }$

$f=\dfrac{2.2\times 10^{14}}{2\pi }\ Hz$

f=3.50×10¹³ Hz

We know that the velocity given as

V = f λ

λ =Wavelength

V=Speed = 3 x 10⁸ m/s

$\lambda =\dfrac{V}{f }$

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λ =0.00000857 m ( 1 μ m = 10⁶ m)

λ =8.57 μ m

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3 years ago

A person travels by car from Tucson to Phoenix at a constant speed of 75 km/hr. They then return from Phoenix to Tucson at a con

kompoz [17]

Answer:

$v=0$

Explanation:

Knowing that the formula for average velocity is:

$v=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}$

Being said that, we know that the person's displacement is zero because it returns to its starting point

$x_{2}=x_{1}$

That means $x_{2}-x_{1}=0$

$v=\frac{0}{t_{2}-t_{1}}=0$

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3 years ago