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MrRissso [65]
3 years ago
11

A student pushes a box with a total mass of 50 kg. What is the net force on the box

Physics
1 answer:
borishaifa [10]3 years ago
8 0

Answer:

75 N

Explanation:

Apply Newton's second law:

∑F = ma

∑F = (50 kg) (1.5 m/s²)

∑F = 75 N

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The formula for potential energy is
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= 342.8 J

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El movimiento de los cuerpos y la formación de imágenes son ejemplos de esta clase de fenómeno ​
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Answer:

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3 years ago
A rotating paddle wheel is inserted in a closed pot of water. The stirring action of the paddle wheel heats the water. During th
fgiga [73]

Answer:

the final energy of the system is 35.5 kJ.

Explanation:

Given;

initial energy of the system, E₁ = 10 kJ

heat transferred to the system, q₁  30 kJ

Heat lost to the surrounding, q₂ = 5kJ

heat gained by the system, Q = q₁ - q₂ = 30 kJ - 5kJ = 25 kJ

work done on the system, W = 500 J = 0.5 kJ

Apply first law of thermodynamic,

ΔU = Q + W

where;

ΔU  is change in internal energy

Q is the heat gained by the system

W is work done on the system

ΔU = 25kJ + 0.5 kJ

ΔU = 25.5 kJ

The final energy of the system is calculated as;

E₂ = E₁ + ΔU

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E₂ =  35.5 kJ.

Therefore, the final energy of the system is 35.5 kJ.

3 0
2 years ago
which fire extinguisher is most appropriate to put out a fire that involves a stack of burning newspapers
evablogger [386]

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6 0
2 years ago
Read 2 more answers
A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second2. What is the net force on the car?
aksik [14]

ANSWER


C. F=4.5 \times10^3. newtons


EXPLANATION


According to Newton's second law,



F_{net}=ma, where



m=1.00\times 10^3kg is the mass measured in kilograms.


and


a=4.5ms^{2} is the acceleration in metres per second square.



We substitute these values to obtain,


F=1.00\times10^3 \times 4.5.



We rearrange to get,


F=1.00\times4.5 \times10^3.


We multiply out the first two numbers and leave our answer in standard form to get,



F=4.5 \times10^3 N.



The correct answer is C


3 0
3 years ago
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