Because there’s like no metal stuff idk
Answer:
about 19.6° and 73.2°
Explanation:
The equation for ballistic motion in Cartesian coordinates for some launch angle α can be written ...
y = -4.9(x/s·sec(α))² +x·tan(α)
where s is the launch speed in meters per second.
We want y=2.44 for x=50, so this resolves to a quadratic equation in tan(α):
-13.6111·tan(α)² +50·tan(α) -16.0511 = 0
This has solutions ...
tan(α) = 0.355408 or 3.31806
The corresponding angles are ...
α = 19.5656° or 73.2282°
The elevation angle must lie between 19.6° and 73.2° for the ball to score a goal.
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I find it convenient to use a graphing calculator to find solutions for problems of this sort. In the attachment, we have used x as the angle in degrees, and written the function so that x-intercepts are the solutions.
In the modern model of the atoms over 99.9℅ of the atom is made up of empty space
Answer:
I can't see the attachment it's too blury I can see bout two words and thats it
Explanation:
Think i got an eye infection or bad eye sight
Answer:
5.42 m/s
Explanation:
At minimum speed, the tension in the bar will be 0 when the ball is at the top of the arc, so the only force is gravity pulling down.
Sum of forces towards the center of the circle:
∑F = ma
mg = m v²/r
v = √(gr)
v = √(9.8 m/s² × 3.00 m)
v = 5.42 m/s