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BARSIC [14]
3 years ago
9

A foal from a red colored mother and a white colored father, has a light red coat. What are the likely genetics behind the foal’

s coloration. What makes you think this?
Biology
1 answer:
kondaur [170]3 years ago
4 0

Answer:

The likely genetics will be incomplete dominance for such a phenomenon.

Explanation:

Incomplete dominance occurs when the dominant allele is not fully or completely showing dominance over the recessive allele.

When parents with such alleles are crossed, the resulting offsprings will show a physical trait which is intermediate and different from both of the parents.

In the scenario discussed in the question, the red colored mother and the white colored father are producing offspring that have light red coat. This is because the red color is not completely dominant over the white color. Hence, an intermediate light red color is seen in the offspring.

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Answer:

The answer is "0.42"

Explanation:

Please find the complete question in the attached file.

Coastal community striped allele intensity = q = 0.62

Landlocked community, strip intensity allele=q'=0.40

Its eliminated allele frequency for movement = q"=0.42 \ in \ indoorscommunity And now in the sturdy vineyard optimum communities, genotype frequency of stripped characteristic (heterozygous device) in coasts=q_2=0.39

Heritable (striped) allele frecency:

\to q=\sqrt{q_2}

      =\sqrt{0.39} \\\\ =0.624 \\\\ =0.62

(round up to the closest cent) is therefore the only frequency of coastal people.

The genome of pulling function in host population= q'_2=0.16 Heterozygous feature regularly.

Therefore the inland community rate of recessed (striped), allele rate:

\to q'= \sqrt{q'_{2}}= \sqrt{0.16}=0.40

Following migration;

Its percentage of coastal migrants:

m=10\% \\\\

   = \frac{10}{100} \\\\= 0.1

Coastal population Non-immigrant percentage of coastal residents:

=1- m\\\\=1-0.1\\\\ =0.9

Stripping coastal community of allele rate after immigration:

(q")=\text{(stripping of migrant only freq)}\times (m)+\text{(stripping allele baud rate for non-immigrants)} \times ( 1-m)

       = [q \times m]+[[q' \times(1-m)]\\\\=(0.62 \times 0.1)+(0.40 \times 0.9)\\\\=0.062+ 0.36\\\\=0.422\\\\=0.42

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