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3 years ago

10

(5×100)+(6×110)+(7×1100) What is this number in standard form?

2 answers:

stepladder [879]3 years ago

8 0

(28-92)+8-29 minutes of friends

yKpoI14uk [10]3 years ago

6 0

(5×100)+(6×110)+(7×1100)=500+660+7700=8860

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Please help with b if you understand

vagabundo [1.1K]

I believe if I'm correct the answer is 2a 3b 4c

0 ? f

Sorry I couldn't figure out the one with the question mark.

7 0

3 years ago

write an equation of the line with the same slope as the line given by 5x+2y=8 and as the same y-intercept as 3x-7y=10

Paladinen [302]

The slope of the first equation would be -5/2 because
2y=-5x+8
y=-5x/2+4
The y intercept of the 2nd equation is when x=0, so -7y=10
y=-10/7
The equation of the line would be y=-5x/2-10/7
Or in standard form....
5x/2+y=-10/7
5x+27=-20/7

5 0

3 years ago

Read 2 more answers

Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)

Fantom [35]

Answer:

Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .

Hence, $\tan(x)$ would be:

$\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}$ .

7 0

2 years ago

Which equation has infinitely many solutions?

Umnica [9.8K]

Answer: B

Step-by-step explanation:

$\dfrac{10x+8}{2} =5x+4\ cross\ products\\\\10x+8=10x+8\\\\0x=0\\$

Every real is solution of the equation .

8 0

2 years ago

2x + 8 = 2(x + 4) help pls

Fynjy0 [20]

2x +8=2x+8
2x-2x=8-8
0x=0
So the answer is 0

7 0

3 years ago

Read 2 more answers