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3 years ago

4. Determine the validity of the following biconditional by

Mathematics

1 answer:

mote1985 [20]3 years ago

3 0

Answer:

be more specific so the gang can help you on this question !!

Step-by-step explanation:

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Which of the following are necessary when proving that the diagonals of a

Flura [38]

Answer:

yes i proved that the opposite side of rectangle are equal by taking triangles in a rectangle and make this triangles are congruent

4 0

3 years ago

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Calculate the perimeter if the value of x is 5.

IceJOKER [234]

Ah u again lol

Perimeter of Isosceles Triangle = 2x + 8
= 2(5) + 8
= 10 + 8
= 18

Therefore, the perimeter is 18. Maybe lol

5 0

3 years ago

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Directions: Calculate the percent increase or decrease between the starting and ending

Sveta_85 [38]

I'll do the first two to get you started

===============================================

Problem 1

A = 3 = starting value

B = 10 = ending value

C = percent change

C = [ (B - A)/A ] * 100%

C = [ (10-3)/3 ] * 100%

C = (7/3) * 100%

C = 2.3333333 * 100%

C = 233.33333%

C = 233.3%

The positive C value means we have a percent increase. If C was negative, then we'd have a percent decrease.

<h3>Answer: 233.3% increase</h3>

===============================================

Problem 2

A = 9 = start value

B = 20 = end value

C = percent change

C = [ (B - A)/A ] * 100%

C = [ (20-9)/9 ] * 100%

C = (11/9)*100%

C = 1.2222222222*100%

C = 122.22222222%

C = 122.2%

<h3>Answer: 122.2% increase</h3>

7 0

3 years ago

Read 2 more answers

PLEASE HELP!!! Maria is saving money so she can go to a professional football game. Maria has $25. She saves $5 a week. Graph a

Kruka [31]

Equation would be: Y = 25 + 5x
Where, x = number of weeks
So, when x = 1, Y = 25 + 5(1) = 25+5 = 30
When x = 2, Y = 25 + 5(2) = 25 + 10 = 35
x = 3, Y = 25 + 5(3) = 25 + 15 = 40

So, Mark the coordinates: (0, 25), (1, 30), (2, 35), (3, 40), (4, 45), (5, 50)...
And draw a line...Graph is done!

Hope this helps!

6 0

3 years ago

Help with the following problem please

Effectus [21]

Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5

By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1

Area of outer circle = $\pi R^2=\pi7^2=49\pi$
Area of large shaded circle = $\pi x^2=\pi5^2=25\pi$
Area of 4 small shaded circles = $4\pi r^2=4\pi1^2=4\pi$
Total area of shaded circles = $25\pi+4\pi=29\pi$

Shaded area as a fraction of that of the outer circle
$=\frac{29\pi}{49\pi}=29/49$

3 0

3 years ago