The momentum of the red cart before the collision is 0.2 kgm/s and the blue cart is 0.
The momentum of the red cart after the collision is 0.05 kgm/s and the blue cart is 0.15 kgm/s.
The change in momentum of the system of the carts is 0.
<h3>
Initial momentum of the carts before collision</h3>
The momentum of the carts before the collision is calculated as follows;
P(red) = 0.5 kg x 0.4 m/s = 0.2 kgm/s
P(blue) = 1.5 x 0 = 0
<h3>Momentum of the carts after collision</h3>
The momentum of the carts after the collision is calculated as follows;
P(red) = 0.5 x 0.1 = 0.05 kgm/s
P(blue) = 1.5 0.1 = 0.15 kgm/s
<h3>Change in momentum of the carts</h3>
![\Delta P = P_f - P_i](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%20P_f%20-%20P_i)
ΔP = (0.05 + 0.15) - (0.2)
ΔP = 0
Learn more about momentum here: brainly.com/question/7538238
A nitrogen atom with 7 protons and 8 neutrons has a mass number of 15amu however on the periodic table the atomic mass for nitrogen is 14.01
Answer:
r(b) = 2.45r
Explanation:
Parameters given:
Satellite A
Mass = m
Orbit radius = r
Satellite B
Mass = 6m
Orbit radius = r(b)
Gravitational force between Earth and Satellite A, F(A) is:
F(A) = (G*M*m)/r²
F(A) = GMm/r²
Gravitational force between Earth and Satellite B, F(B) is:
F(B) = (G*M*6m)/r(b)²
F(B) = 6GMm/r(b)²
Since F(A) = F(B),
GMm/r² = 6GMm/r(b)²
=> r(b)² = 6r²
r(b) = 2.45r
Answer:
It is given that the image is formed at a distance of 50cm from the lens. And since the image is real, v = +50cm. This means that u = -50cm. Therefore, the needle must be placed at a distance of 50cm from the lens.
Explanation: