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Alekssandra [29.7K]
3 years ago
14

ORGANISMS THAT ARE EATEN BY OTHER ANIMALS ARE CALLED

Chemistry
2 answers:
Romashka [77]3 years ago
8 0
I believe they are preys? and the ones who eat are predators. 
marishachu [46]3 years ago
4 0
ANSWER is prey. Predators are the animals that eat other animals, while prey are the animals that get eaten.
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Determine the charge on each ion in the following compounds, and name the compound. Spelling counts!
lisabon 2012 [21]
I can't really answer his if there is no given. However, there are general rules to follow when naming ionic compounds. For example, if the given compound is written as: MgCl₂. 

There are two elements that we could find: Mg and Cl. The rule is to write the positive ion first, followed by the negative ion. The individual charges of each element is the subscript of the other. Since Cl has a subscript of 2, then Mg has a charge of +2. Since Mg has a subscript of 1, then Cl has a charge of -2.

Finally, the rule of naming the ionic compound is to name the ions individually in order, but you have to take the suffix -ide (if the charge is -1). Thus, the name of the compound is Magnesium Chloride,
4 0
3 years ago
Read 2 more answers
In this reaction, what roll does the lead (II) nitrate play when 50.0 mL of 0.100M iron (III) chloride are mixed with 50.0 mL of
scoundrel [369]
Lead(II) nitrate will react with iron(III) chloride to produce the precipitate lead(II) chloride as shown in the balanced reaction
     2FeCl3(aq) + 3Pb(NO3)2(aq) → 2Fe(NO3)3(aq) + 3PbCl2(s)   
Calculating the amount of the precipitate lead(II) chloride each reactant will produce: 
     mol PbCl2 = 0.050L Pb(NO3)2 (0.100mol/1L)(3mol PbCl2/3mol Pb(NO3)2)
                       = 0.00500mol PbCl2
     mol PbCl2 = 0.050L FeCl3 (0.100mol FeCl3/1L)(3mol PbCl2/2mol FeCl3)                                 = 0.00750mol PbCl2
The reactant Pb(NO3)2 produces a lesser amount of the precipitate PbCl2, therefore, the lead(II) nitrate is the limiting reagent for this reaction.
8 0
3 years ago
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speed v=s/t=1930.8÷144=[tex] \frac{1930.8}{144} = \frac{160.9}{12} =[/13.408m/s ~nearly]
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What do you think would happen if you had a very small amount of water in a glass and you
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If it was warn - hot water, i would say yes



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