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2 years ago

ORGANISMS THAT ARE EATEN BY OTHER ANIMALS ARE CALLED

Chemistry

2 answers:

Romashka [77]2 years ago

8 0

I believe they are preys? and the ones who eat are predators.

marishachu [46]2 years ago

4 0

ANSWER is prey. Predators are the animals that eat other animals, while prey are the animals that get eaten.

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How many moles are in 7950 g of CO2? ( pleas show calculation)

Mkey [24]

Answer:

Calculate the number of moles of CO2 by the formula n=PV/RT, where P is the pressure from Step 3, V is the volume from Step 2, T is the temperature from Step 1 and R is a proportionality constant equal to 0.0821 L atm / K mol.

Explanation:

6 0

2 years ago

How many grams are there in 3.4 x 10^24 atoms of He?

Lelechka [254]

Given :

Number of He atoms, $n = 3.4\times 10^{24}$ atoms.

To Find :

How many grams are their in given number of He atoms.

Solution :

We know, molecular mass of He is 4 g. It means that their are $6.022 \times 10^{23}$ atoms in 4 g of He.

Let, number of gram He in $3.4\times 10^{24}$ atoms is x , so :

$x = \dfrac{3.4\times 10^{24}}{6.022\times 10^{23}}\times 4\\\\x = $$22.58\ g$

Therefore, grams of He atoms is 22.58 g .

5 0

2 years ago

given a mixture of lead to oxide ammonium chloride and sodium chloride describe how a mixture can be separated to obtain a sampl

wariber [46]

Answer:

There are way in separating mixtures of chloride salts such as that of sodium chloride and ammonium chloride. It can be done by crystallization, filtration, and sublimation. The easiest method among the three is separation by sublimation.

5 0

2 years ago

You have 500 mL of 5 M HCl already made. You need to dilute the solution to 1 M HCl. How much water will you need to add?

hram777 [196]

Answer:

You need to add 400mL of water

Explanation:

500mL = 5 M HCI That means that if you divide both sides by 5

100mL = 1 M HCI If you need ot get rid of 4 M HCI then you add 400 mL of water because that is what it is equal to

5 0

3 years ago

Draw all four products obtained when 2-ethyl-3-methyl-1,3-cyclohexadiene is treated with HBr at room temperature and show the me

LenKa [72]

Answer:

See explanation below

Explanation:

In this case we have reaction of addition. In this case a diene reacting with an acid as HBr. This reaction is known as Hydrohalogenation, and, as we have a diene, this kind of reaction can be done as 1,4 addition. Which means that the reaction will be undergoing with an adition in the carbon 1, and carbon 4.

At room temperature we can expect that this reaction can be done in thermodynamic conditions, Now, as the problem states that is forming 4 products, we can expect products of a 1,2 addition too. This product can be formed if the reaction is taking place in the most stable carbocation, and then, by resonance, we can expect the 1,4 product too.

Now, the HBr can be attacked by the double bond of the first position, giving two possible products or by the double bond of the third position giving the other two products. These products are all possible, obviously the most stable will be the major of all of them, but the other three are perfectly possible. One product is formed without doing much, and the other by resonance. Same happens with the other double bond.

In the picture below, you have the mechanism for all the 4 products.

Hope this helps

5 0

2 years ago