Answer:
i have an answer but i can only show you because my teacher helped my on it and wrote it down for me to remember! hope this helps!!!
Explanation:
A 1.00 g sample ofn-hexane (C6H14) under-goes complete combustion with excess O2ina bomb calorimeter. The temperature of the1502 g of water surrounding the bomb risesfrom 22.64◦C to 29.30◦C. The heat capacityof the hardware component of the calorimeter(everything that is not water) is 4042 J/◦C.What is ΔUfor the combustion ofn-C6H14?One mole ofn-C6H14is 86.1 g.The specificheat of water is 4.184 J/g·◦C.1.-9.96×103kJ/mol2.-7.40×104kJ/mol3.-1.15×104kJ/mol4.-4.52×103kJ/mol5.-5.92×103kJ/molcorrectExplanation:mC6H8= 1.00 gmwater= 1502 gSH = 4.184 J/g·◦CHC = 4042 J/◦CΔT= 29.30◦C-22.64◦C = 6.66◦CThe increase in the water temperature is29.30◦C-22.64◦C = 6.66◦C. The amount ofheat responsible for this increase in tempera-ture for 1502 g of water isq= (6.66◦C)parenleftbigg4.184Jg·◦Cparenrightbigg(1502 g)= 41854 J = 41.85 kJThe amount of heat responsible for the warm-ing of the calorimeter isq= (6.66◦C)(4042 J/◦C)= 26920 J = 26.92 kJ
Answer:
"An equilibrium constant expression describes the relationship among the concentrations (or partial pressures) of the substances present in a system at equilibrium" (General Chemistry). ... For this example, Ka = 2.2 x 10-4 and the initial concentration of HA, the acid in solution is 2 mol L-1.
Answer:
36.28 kg
Explanation:
Given data:
Gravitational potential energy of object = 800 J
Height from ground = 2.245 m
Mass of object = ?
Solution:
Formula:
P.E = mgh
g =acceleration due to gravity = 9.8 m/s²
by putting values,
800 J = m× 9.8 m/s² ×2.25 m
J = kgm²/s²
800 kgm²/s² = m× 22.05 m²/s²
m = 800 kgm²/s² /22.05 m²/s²
m = 36.28 kg
It would be D since it could be unhealthy for you.
