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3 years ago

Write the detailed structure of A. C2H6 B. C4H10 C. C6H14 D. C7H16

Chemistry

2 answers:

STALIN [3.7K]3 years ago

8 0

H₃C-CH₃

this is called ethane

H₃C-CH₂-CH₂-CH₃

this is called butane

C.H₃C-CH₂-CH₂-CH₂-CH₂-CH₃

this is called hexane

H₃C-CH₂-CH₂-CH₂-CH₂-CH₂-CH₃

this is called heptane

KATRIN_1 [288]3 years ago

4 0

Answer:

1. a) Ethane (C2H6)

2. b) Butane (C4H10 )

3. c) Hexane (C6H14)

4. d) Heptane (C7H16)

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An element X that has 15 protons and 15 electrons, loses three

Wewaii [24]

Answer:

12 electrons and 15 protons.

Explanation:

The element having 15 electrons and 15 protons have atomic number 15. We know that when an atom lose or gain the electron ions are formed.

Anion formation:

Anion is formed when electron is accept by an atom.

X + e⁻ → X⁻

Cation formation:

Cation is formed when electron lose be an atom.

X → X⁺ + e⁻

The given atom loses 3 electrons thus oxidation number will be +3 and cation is formed.

X → X³⁺ + 3e⁻

Now element X have 15 protons and 12 electrons.

8 0

3 years ago

A mixture of gaseous reactants is put into a cylinder, where a chemical reaction turns them into gaseous products. The cylinder

IRISSAK [1]

Answer:

A. Up

B. Out

C. Out

D. To equilibrum

Explanation:

a. The reaction in an exothermic reaction so this means heat is given off. If the cylinder is thin enough heat will transfer to the water bath

b. Since the products will create heat which will increase pressure, the piston in an attempt to maintaining a constant pressure will move up to accommodate building pressure.

c. Heat will flow out of the gaseous mixture as this reaction creates heat as a product as well

d. Heat will flow out in the capacity to create an equilibrium with the water bath that it is in.

7 0

3 years ago

Suppose that a 10-mL sample of a solution is to be tested for I− ion by addition of 1 drop (0.2 mL) of 0.13 M Pb(NO3)2.

Liono4ka [1.6K]

The minimum number of grams of I that must be present is ; 0.01836 * 10⁻³ mol

Given data :

Volume of solution to be tested for I-ion = 10 mL

Volume of Pb(NO₃)₂ = 0.2 mL

molarity of Pb(NO₃)₂ = 0.13 M

<h3>Determine the number of I that must be present </h3>

First step : calculate conc of PB²⁺ ions in the solution

conc of PB²⁺ ions = ( molarity of Pb(NO₃)₂ * volume of Pb(NO₃)₂ ) / ( total volume )

= ( 0.13 * 0.2 ) / ( 10 + 0.2 )

= ( 0.026 ) / ( 10.2 ) = 0.002549 M

Next step : determine the molarity of I

using the dissociation reaction of PbI₂

PbI₂(s) ---> Pb²⁺ (aq) + 2I (aq)

also; Ksp = [ Pb²⁺ ] [ I ]² ---- ( 1 )

From the question the given value of Ksp = 8.49 * 10⁻⁹

Therefore equation ( 1 ) becomes

8.49 * 10⁻⁹ = ( 0.002549 ) * [ I ]²

[ I ] = √ ( 8.49 * 10⁻⁹ ) / ( 0.002549 )

= 0.0018 M

Final step : Determine the minimum number of grams of I

moles of I = molarity of I * total volume

= 0.0018 M * 10.2 mL

= 0.01836 * 10⁻³ mol

Hence we can conclude that The minimum number of grams of I that must be present is ; 0.01836 * 10⁻³ mol

Learn more about Pb(NO₃)₂ : brainly.com/question/25071409

8 0

2 years ago

What is the hybridization of sb in the molecule sbcl52–? antimony (sb) can accept up to twelve electrons?

Setler79 [48]

The valence electron configuration for antimony (Sb) is:

Sb = 5s²5p³5d⁰

In SbCl₅²⁻, antimony has a -2 charge i.e. it has 2 additional electrons

Sb²⁻ = 5s²5p⁵5d⁰

Following a two electron transition from p→d orbital we have:

Sb²⁻ = 5s²5p³5d²

There is a total of 5 unpaired electrons (3 in the p and 2 in the d) which can form five bonds with the 5 Cl atoms.

Thus the hybridisation of Sb in SbCl₅²⁻ is sp³d²

5 0

3 years ago

Read 2 more answers

write the balanced equation for the reaction that occurs when butane undergoes combustionWhat is the coefficient of oxygen in th

love history [14]

Answer:

2C4H10 + 13O2 ----> 4CO2 + 10H2O

The coefficient of oxygen in the balanced equation is 13

5 0

3 years ago