if your wondering what 7 times 3073 is then your answer is 21511. If your looking for something else I don't understand it then. Hope this helps!
Answer:
The answer is "Option A and Option B".
Step-by-step explanation:
In question 1:
In all cases, the entire population is measured so that the actual medium discrepancy could be measured as well as an interval of trust cannot be used.
This issue would be that she calculated the ages with all representatives of both classes, such that she measured a whole population. It's not necessary.
In question 2:
When the p-value is 0.042. At 90% trust and 92% trust level 11 (p-value below 0.10 and 0.08) are not included. however the biggest confidence level of 92%. Consequently, the largest trust level where the 11 is Not included in the trust interval is 92% trust.
Answer:
it is 4
Step-by-step explanation:
3 times 4 = 12 and 12 + 8 = 20
brainliest plz!!!
Answer:
a
Step-by-step explanation:
Given Information:
number of trials = n = 1042
Probability of success = p = 0.80
Required Information:
Maximum usual value = μ + 2σ = ?
Minimum usual value = μ - 2σ = ?
Answer:
Maximum usual value = 859.51
Minimum usual value = 807.78
Step-by-step explanation:
In a binomial distribution, the mean μ is given by
μ = np
μ = 1042*0.80
μ = 833.6
The standard deviation is given by
σ = √np(1 - p)
σ = √1042*0.80(1 - 0.80)
σ = √833.6(0.20)
σ = 12.91
The Maximum and Minimum usual values are
μ + 2σ = 833.6 + 2*12.91
μ + 2σ = 833.6 + 25.82
μ + 2σ = 859.51
μ - 2σ = 833.6 - 25.82
μ - 2σ = 807.78
Therefore, the minimum usual value is 807.78 and maximum usual value is 859.51
