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marshall27 [118]
4 years ago
15

How many 4 digit codes are possible if the first digit cannot be 0 and digits can be repeated?

Mathematics
1 answer:
bezimeni [28]4 years ago
4 0

Answer: 9,000

Step-by-step explanation: there are 9 number options for the first digit and 10 for the other 3, so 9x10x10x10=9000

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o-na [289]
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3 0
3 years ago
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Inga [223]
10-7=3, 7-5=2 so the pattern is -3,-2
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3 years ago
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6 0
3 years ago
0.099
ioda
The answer to your question is 0.469
3 0
3 years ago
(12y + 12) - 21y<br><br> Simplify each expression using the properties of numbers.
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