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marshall27 [118]
3 years ago
15

How many 4 digit codes are possible if the first digit cannot be 0 and digits can be repeated?

Mathematics
1 answer:
bezimeni [28]3 years ago
4 0

Answer: 9,000

Step-by-step explanation: there are 9 number options for the first digit and 10 for the other 3, so 9x10x10x10=9000

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3 years ago
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tankabanditka [31]

Answer:

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-3x + y = 21        -----------(II)

Add equation (I) & (II) and so x will be eliminated and we can find the value of y.

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(II)    <u> -3x + y = 21  </u>      {add}

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8 0
3 years ago
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