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Vikentia [17]
3 years ago
10

The social studies teacher wants to know whether the students in the entire school prefer a model United Nations activity or a s

tudent government activity. The teacher draws a random sample from the following groups:
All teachers in the school
All boys in each grade
All students in each grade
All students in the social studies club
Which group best represents the population he should take a random sample from to get the best results for his survey?


All teachers in the school
All boys in each grade
All students in each grade
All students in the social studies club
Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

All students in each grade.

Step-by-step explanation: This is the answer that givs the most variablity. Your welx if its correct :)

dedylja [7]3 years ago
3 0
That would be number 3 on the list; All students in each grade
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Answer: G

Explanation/Calculation:

You can clearly see that the white shapes are positive while the black shapes are negative. You can determine this because all (except F) claim that the 6 shapes are negative.

To make it easier, use elimination. It's definitely not J because you are not subtracting -6, but adding (as seen in the equation.) It is not F because 2(3)=6 when the equation needs -6.

So it is either G or H...

H claims that 12x+3+(-6) is what the model symbolizes; but this is incorrect. Unless x is a decimal, you can not have the large shape as the "purest" form (so to speak.) The "purest" state you can go in this model is a cube/square which=1.

Therefore, "G Jamey modeled 12 + 3x + (-6) and it is equivalent to 12x-3" is the correct answer.

Hope this helps you!
8 0
3 years ago
How many minutes are in 2 3/5 hours
Temka [501]
156 minutes are in 2 and 3/5 of an hour. 
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3 years ago
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The equation 12x² + 4kx + 3 = 0 has real and equal roots, if
sleet_krkn [62]

Answer:

k=\pm3

Step-by-step explanation:

[...] if you can write the LHS as a perfect square, or if you can't spot a factorization of it right away, if and only if the discriminant \Delta = b^2-4ac (or, if b is an even number, 1/4 of it) is zero.

<u>I see it! I see it!</u>

Stare at it for a while. First term is 3(2x)^2, third term is 3(1)^2, we are missing a double product, but we can play with k. For the LHS to be 3(2x\pm1)^2 = 3(4x^2\pm4x+1) = 12x^2\pm12x+3 you just need 4k= \pm12 \rightarrow k=\pm3.

<u>I don't see it...</u>

Then number crunching it is. Set the discriminant to 0, solve for k

\frac{\Delta}4 = 4k^2-12\cdot 3 =0 \rightarrow 4k^2=36 \\k^2 = 9 \rightarrow k=\pm3

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olganol [36]

Answer:

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0.79 pounds for a dollar costs less than 1.31 pounds for a dollar

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3 years ago
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